Question

我正在建立一个django多站点，他们是博客站点，有一个主站点和许多其他子站点。

所以我有不同网站的不同设置文件，每个设置都会导入主设置并覆盖特定值，子网站设置的示例如下所示：

import os
from os.path import join, dirname

PROJECT_ROOT = dirname(dirname(__file__))
VIRTUALENV_ROOT = dirname(PROJECT_ROOT)

try:
    from settings import *
except: pass

SITE_ID = 3 
SITE_NAME = 'child1'

TEMPLATE_DIRS = ( 
    join(PROJECT_ROOT, 'templates', SITE_NAME),
    join(PROJECT_ROOT, 'templates', 'master'),
    join(PROJECT_ROOT, 'templates'),
)

STATIC_ROOT = join(VIRTUALENV_ROOT, 'public-www', 'static', SITE_NAME)

STATIC_URL = '/static/{}/'.format(SITE_NAME)

STATICFILES_DIRS = ( 
    join(PROJECT_ROOT,'static', SITE_NAME),
    join(PROJECT_ROOT,'static'),
)

HAYSTACK_CONNECTIONS = {.
    'default': {
        'ENGINE': 'haystack.backends.whoosh_backend.WhooshEngine',
        'PATH': os.path.join(VIRTUALENV_ROOT, 'whoosh_index', SITE_NAME),
    },..
}

如果我为每个站点手动重建索引，它们都可以正常工作。这是search_indexes：

import datetime
from haystack import indexes
from articles.models import Story
from django.contrib.sites.models import Site

current_site = Site.objects.get_current()

class StoryIndex(indexes.SearchIndex, indexes.Indexable):
    text = indexes.CharField(document=True, use_template=True)
    title = indexes.CharField(model_attr='title')
    introtext = indexes.CharField(model_attr='introtext')
    content = indexes.CharField(model_attr='content')
    author = indexes.CharField(model_attr='author')

    def get_model(self):
        return Story

    def index_queryset(self, using=None):
        return Story.active_objects.filter(sites__in=[current_site])

但是，我需要在主站点上创建文章，并选择要在哪些站点上显示文章。

问题是在主站点上创建文章时，它只更新主索引，而不更新子站点的索引。有一种聪明的方法吗？

Answer 1

当前适合我的工作是使用单一搜索索引，使用多值字段进行网站选择，例如：

sites = MultiValueField()

def prepare_sites(self, obj):
    return [site.domain for site in obj.sites.all()]

然后编写我自己的搜索查询：

from haystack.query import SearchQuerySet
from django.contrib.sites.models import Site
from django.shortcuts import render

current_site = Site.objects.get_current()

def search(request):
    cx = {}
    query = request.GET.get('q', '')
    cx['query'] = query
    cx['result'] = SearchQuerySet().filter(content=query, sites__in=[current_site.domain])
    return render(request, 'search/search.html', cx)

Django Haystack多站点索引

1 个答案: