Question

我一直试图用PHP和MySQL创建登录代码。当我单击登录按钮时，即使用户名和密码正确，它也不会转到下一页：它只是刷新login.php页面。我不确定我的代码中存在什么问题。

此相同的代码适用于本地服务器，但在互联网上则不然。

       <?php
session_start();
include './db_connect.php';

$error = " " ;
if(isset($_POST['submit'])){
    $username = $_POST['username'];
    $password =md5($_POST['password']);
    if((!isset($username)) || ($username=="") || (!$username == " ") || (!isset($password)) || ($password=="") || (!$password == " ")){
    $error = "Please enter the details";
    }
    else{
         $username = $_POST['username'];
         $password =md5($_POST['password']);

        $query = mysql_query("SELECT * FROM admin WHERE admin_name = '".$username."' and password = '".$password."'");

                $row = mysql_fetch_array($query);
                 $username_db = $row['admin_name'];
                 $password_db = $row['password'];



                if(($username == $username_db) && ($password ==$password_db) )
                                    {  
                                    header ("Location:admin_hotel_details.php");
                                       $_SESSION['username']=$username_db;

                    }

                    else{

                        $error = "Username and password do not    match";

                        }

        }   
  }

   ?>

这是admin.php（我的表格代码）

<form name="" action="admin.php" method="post">
      <style type="text/css">
      label{width:130px;}
      </style>
      <table cellpadding="4" style="margin-left:10px;">
                <tr>
      <td colspan="2"><span style="color:#F00;">
      <?php
      if(isset($_GET['msg'])){
      $msg = $_GET['msg'];
      $error = "Successfully logged out";
      }
      if(isset($error)){echo $error;} 
      ?>
      </span></td>
      </tr>



      <tr>
      <td style="width:150px;"><label for="username">Username: <span style="color:#F00;">*</span>:</label></td>
      <td style="width:100px;">
      <input type="username" name="username" id="username" onkeyup="javascript:this.value=this.value.toUpperCase();" style="width:205px" />
      </td>
      </tr>


      <tr>
      <td style="width:100px;"><label for="password">Password:<span style="color:#F00;">*</span>:</label></td>
      <td style="width:100px;"><input type="password" name="password" onkeyup="javascript:this.value=this.value.toUpperCase();" id="password" style="width:205px;" /></td>
      </tr> 



      <tr>
      <td>&nbsp;</td>
      </tr>

      <tr>
      <td>&nbsp;</td>
      <td style="width:100px;">
      <input type="submit" name="submit" id="submit" value="Login"/>
      <input type="reset" name="reset" id="reset" value="Reset"/>
      </td>
      </tr>  

      </table>
      </form>

我也试过了不同的login.php

         <?php 

    include("./db_connect.php");
    session_start();
    $error = " " ;
    if ($_SERVER["REQUEST_METHOD"] == "POST") {
        // Username and password sent from form in HTML
        $myusername = $_POST['username'];
        $mypassword = md5($_POST['password']);

        $sql    = "SELECT * FROM admin WHERE admin_name = '".$myusername."' and password ='".$mypassword."'";
        $result = mysql_query($sql) or die(mysql_error($sql));
        $row    = mysql_fetch_array($result);

        $count  = mysql_num_rows($result);

        // If result matched $myusername and $mypassword, table row must be 1 row
        if ($count == 1) {

            $_SESSION['login_user'] = $myusername;

            header("location:admin_hotel_details.php");
        } else {
            $error = "Your username or password is invalid";
        }
    }
   ?>

这给了我同样的问题（在标题处）。

Answer 1

在这里，我尝试根据我发布的评论稍微清理一下你的代码。看看这是否适合你。

<?php
    session_start();
    include './db_connect.php';

    $error = " " ;
    if(isset($_POST['submit']) && isset($_POST['username']) && isset($_POST['password'])){
        $username = $_POST['username'];
        $password =md5($_POST['password']);
        if($username=="" || $password==""){
            $error = "Please enter the details";
        }else{
            $result = mysql_query("SELECT * FROM admin WHERE admin_name = '".$username."' and password = '".$password."'");

            if(mysql_num_rows($result)>0){  
                $_SESSION['username']=$username;
                header("Location:admin_hotel_details.php");
            }else{
                $error = "Username and password do not match";
            }
        }   
    }
?>

Answer 2

尝试错误地使用脚本。

        header("location: admin_hotel_details.php");
        exit();
    }else {
        //Login failed
            echo "<script>alert('INVALID USERNAME OR PASSWORD!');
                window.location='index.php';
                </script>";

为什么这个login.php不起作用？

2 个答案: