如何获取表中现在行的下一行和上一行

Question

STRUCTURE TABLES AND ERROR WHEN EXECUTE QUERY ON SQLFIDDLE

我有表News。

例如，我得到NewsIdn = '164955'：

的行

SELECT * FROM News WHERE NewsIdn = '164955'

上一行有NewsIdn = '270085'，下一行有NewsIdn = '324955'。

请告诉我如何使用mysql查询获取上一个NewsIdn和下一个NewsIdn？

Answer 1

也许是这样的：

主要查询：

SELECT * FROM News WHERE NewsIdn = '164955';

上一行：

select * from News WHERE ID < 
    (select ID from News where NewsIdn = '164955') Order by ID DESC Limit 1;

下一行：

select * from News WHERE ID > 
    (select ID from News where NewsIdn = '164955') Order by ID Limit 1;

Answer 2

试试这个：

一个：

SELECT * FROM News WHERE NewsIdn < '164955' ORDER BY NewsIdn DESC LIMIT 1

下一步：

SELECT * FROM News WHERE NewsIdn > '164955' ORDER BY NewsIdn LIMIT 1