Question

我正在编写休息服务。我尝试回复的对象是通用的：

public class ResultadoBaseJsonForm<ID extends Serializable,E> implements Serializable{

private String resultado;
private String mensaje;
private List<ObjectError> errores;
private Map<String,String> erroresValidacion;
private ID id;
private E obtjetoTransporte;

实施的对象是：

ResultadoBaseJsonForm<Long,List<Reference>>

在客户端，代码为：

Gson gson = new Gson();
Type collectionType = new TypeToken<ResultadoBaseJsonForm<Long, List<Reference>>>(){}.getType();
ResultadoBaseJsonForm<Long, List<Reference>> objectResponse =   gson.fromJson(jsonresult, collectionType);

消息是：

{"resultado":"OK","mensaje":"Referencias consultadas correctamente","errores":null,"erroresValidacion":null,"id":null,"obtjetoTransporte":[{"code":"140.12","type":"1","family":"1","tittle":"1","descripcion":"1","drawable":"","drawableSmall":""},"code":"140.6","type":"1","family":"1","tittle":"1","descripcion":"1","drawable":"","drawableSmall":""}]}

我收到了这个错误：

The JsonDeserializer com.google.gson.DefaultTypeAdapters$CollectionTypeAdapter@a7415fb0 failed to deserialized json object 
[{"code":"140.12","type":"1","family":"1","tittle":"1","descripcion":"1","drawable":"","drawableSmall":""},{"code":"140.6","type":"1","family":"1","tittle":"1","descripcion":"1","drawable":"","drawableSmall":""}] given the type java.util.List<com.six.tma.bean.Reference>

参考类是：

public class Reference implements Serializable, Cloneable {
@DatabaseField(id = true) 
private String code;

@DatabaseField(canBeNull=false)
private String family;
@DatabaseField
private String tittle;
@DatabaseField(canBeNull=false)
private String type;
@DatabaseField
private String descripcion;
@DatabaseField
private String promotion;
@DatabaseField
private String mechanic;
@DatabaseField
private String period;
@DatabaseField
private String quota;

@DatabaseField(dataType = DataType.BYTE_ARRAY)
private byte[] drawable;
@DatabaseField(dataType = DataType.BYTE_ARRAY)
private byte[] drawableSmall;

任何帮助？

抱歉，我附上了错误的JSON：

{"resultado":"OK","mensaje":"Referencias consultadas correctamente","errores":null,"erroresValidacion":null,"id":null,"obtjetoTransporte":[{"code":"140.12","type":"1","family":"1","tittle":"1","descripcion":"1","drawable":"","drawableSmall":""},{"code":"140.6","type":"1","family":"1","tittle":"1","descripcion":"1","drawable":"","drawableSmall":""}]}

我在jsonlint.org点击测试了它，它是有效的。我在春天做了它。

任何帮助？

Answer 1

您的JSON错误，我不知道您是如何在服务器端生成的，但在第二个“代码”令牌之前缺少[。

如果你有一个用Java编码的服务器，你也可以使用Gson序列化你的响应。

正如评论中所建议的那样，您可以利用http://json.parser.online.fr/等服务检查JSON，以便在解析错误时检查您的JSON。

GSON Generic：无法反序列化json对象

1 个答案: