Question

我正在尝试使用Python和Julia实现基本的客户端 - 服务器套接字结构，其中生产者是Python，消费者是Julia。

我在Python端的代码如下所示：

def startServer(host='127.0.0.1', port=4002):
  connected = False
  s = socket.socket()
  s.bind((host, port))
  s.listen(5)
  scon, addr = s.accept()
  print 'Got connection from', addr
  return scon, addr

在Julia方面，它看起来像这样：

using PyCall

@pyimport server as sdlib

@async begin
  sleep(10)
  print("In the async thread\n")
  s,a = sdlib.startServer("127.0.0.1",4002)
  print("Server started\n")
end

print("After the async thread\n")
print("Connecting...\n")
connected = false
while !connected
  try
    connected = true
    c = connect(4002)
    print("Connected = $(connected), $(c)\n")
  catch ex
    print("$(ex)\n")
    connected = false
    sleep(1)
  end
end
print("Connection established: $(c)\n")

输出如下：

After the async thread
Connecting...
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
connect: connection refused (ECONNREFUSED)
In the async thread

似乎正在发生的事情是，一旦Python侦听器启动，线程就会锁定等待连接。 Control似乎永远不会传回主线程以允许客户端连接。

感谢我能得到的任何帮助。

谢谢，拉维

Answer 1

我远离我的知识领域，但由于没有人在10小时内回答，我会尝试。

我认为问题在于julia没有积极的调度程序。您可以使用并发功能，但它们将在同一进程中协同安排。由于PyCall不返回或调用（julia？）睡眠，控件将不会返回到客户端。你可以试试addprocs或用-p 2开始julia，但我不确定它会有用。

另请参阅http://docs.julialang.org/en/release-0.2/manual/parallel-computing/，以便更好地解释这一点。

与PyCall一起使用时Julia中的异步线程死锁

1 个答案: