Question

如何找到oracle中两个日期之间的区别？

我尝试使用Extract方法，但效果不正常。

格式应为 hh：mm：ss

Answer 1

EXTRACT适用于日期时间或间隔值表达式。当您减去两个日期时，您会得到一个数字，即天数。如果你想使用提取你应该使用NUMTODSINTERVAL将其转换为区间数据类型，然后使用EXTRACT。

SELECT   TO_DATE ('14-01-2014 14:00:00', 'dd-mm-yyyy hh24:mi:ss')
       - TO_DATE ('13-01-2014 22:30:45', 'dd-mm-yyyy hh24:mi:ss')
  FROM DUAL;

0.6453125

SELECT NUMTODSINTERVAL (
            TO_DATE ('14-01-2014 14:00:00', 'dd-mm-yyyy hh24:mi:ss')
          - TO_DATE ('13-01-2014 22:30:45', 'dd-mm-yyyy hh24:mi:ss'),
          'DAY')
  FROM DUAL;

+00 15:29:15.000000

SELECT    EXTRACT (HOUR FROM intrvl)
       || ':'
       || EXTRACT (MINUTE FROM intrvl)
       || ':'
       || EXTRACT (SECOND FROM intrvl)
  FROM (SELECT NUMTODSINTERVAL (
                    TO_DATE ('14-01-2014 14:00:00', 'dd-mm-yyyy hh24:mi:ss')
                  - TO_DATE ('13-01-2014 22:30:45', 'dd-mm-yyyy hh24:mi:ss'),
                  'DAY')
                  AS intrvl
          FROM DUAL);

15:29:15

您甚至可以将日期转换为时间戳，以便差异已经是interval数据类型。

SELECT    EXTRACT (HOUR FROM intrvl)
       || ':'
       || EXTRACT (MINUTE FROM intrvl)
       || ':'
       || EXTRACT (SECOND FROM intrvl)
  FROM (SELECT   CAST (
                    TO_DATE ('14-01-2014 14:00:00', 'dd-mm-yyyy hh24:mi:ss') AS TIMESTAMP)
               - CAST (
                    TO_DATE ('13-01-2014 22:30:45', 'dd-mm-yyyy hh24:mi:ss') AS TIMESTAMP)
                  AS intrvl
          FROM DUAL);

oracle中两个日期之间的差异

1 个答案: