迫使NSPopover成为NSTokenField的第一响应者

Question

我有一个NSTokenField，我在popover中提供自定义自动完成功能。不幸的是，一旦弹出窗口显示它就迫使NSTokenField辞职第一响应者。有没有办法显示弹出窗口而不是松开NSTokenField上的第一个响应者？

覆盖NSTokenField的resignFirstResponder会导致NSTokenField停止工作（它不接受任何击键）。覆盖NSPopover的acceptedFirstResponder方法或按this问题中的建议设置其行为也不起作用。

编辑：NSTokenField不在NSPopover的contentViewController.view中。 Edit2：像Mailapp中搜索栏的行为将是最佳解决方案。

Answer 1

不幸的是，没有干净的方法可以做到这一点。幸运的是，我在Delicious Library 3中做了一个丑陋的方法 - 你需要把这个方法放在NSWindow的子类中，并确保有问题的文档窗口是那个子类：

- (BOOL)makeFirstResponder:(NSResponder *)responder;
{
    // Prevent popover content view from forcing our current first responder to resign
    if (responder != self.firstResponder && [responder isKindOfClass:[NSView class]]) {
        NSWindow *const newFirstResponderWindow = ((NSView *)responder).window;
        NSWindow *currentFirstResponderWindow;

        NSResponder *const currentFirstResponder = self.firstResponder;
        if ([currentFirstResponder isKindOfClass:[NSWindow class]])
            currentFirstResponderWindow = (id)currentFirstResponder;
        else if ([currentFirstResponder isKindOfClass:[NSView class]])
            currentFirstResponderWindow = ((NSView *)currentFirstResponder).window;

        // Prevent some view in popover from stealing our first responder, but allow the user to explicitly activate it with a click on the popover.
        // Note that the current first responder may be in a child window, if it's a control in the "thick titlebar" area and we're currently full-screen.
        if (newFirstResponderWindow != self && newFirstResponderWindow != currentFirstResponderWindow && self.currentEvent.window != newFirstResponderWindow)
            for (NSView *responderView = (id)responder; responderView; responderView = responderView.superview)
                if ([responderView conformsToProtocol:@protocol(LIPopoverFirstResponderStealingSuppression)] &&
                    ((id <LIPopoverFirstResponderStealingSuppression>)responderView).suppressFirstResponderWhenPopoverShows)
                    return NO;
    }

    return [super makeFirstResponder:responder];
}

现在确保popover的内容视图子类实现此协议：

// NSPopover doesn't respect -acceptsFirstResponder of its content view (Radar 10666891).
@protocol LIPopoverFirstResponderStealingSuppression <NSObject>
@property (readonly, nonatomic) BOOL suppressFirstResponderWhenPopoverShows;
@end

请同时向Apple提交错误请求NSPopover尊重-acceptsFirstResponder的内容视图; 100％的情况是，当多个开发人员提交错误时，他们会得到修复。

Answer 2

制作popover内容的子类（文本视图？）并实现-(void)canBecomeKeyView。那边还没有。当弹出窗口显示时，它只被调用一次，因此您仍然可以与它进行交互，但它不会再盗取第一个响应者状态。

Answer 3

我修改了Will对Swift的回答：

protocol PopoverFirstResponderStealingSuppression {
    var suppressFirstResponderWhenPopoverShows: Bool { get }
}

class TTWindow: NSWindow {
    override func makeFirstResponder(_ responder: NSResponder?) -> Bool {
        if responder != firstResponder, let responderView = responder as? NSView {
            // Prevent popover content view from forcing our current first responder to resign

            let newFirstResponderWindow = responderView.window!
            var currentFirstResponderWindow: NSWindow? = nil

            let currentFirstResponder = firstResponder
            if let currentFirstResponder = currentFirstResponder as? NSWindow {
                currentFirstResponderWindow = currentFirstResponder
            }
            else if let currentFirstResponder = currentFirstResponder as? NSView {
                currentFirstResponderWindow = currentFirstResponder.window
            }

            // Prevent some view in popover from stealing our first responder, but allow the user to explicitly activate it with a click on the popover.
            // Note that the current first responder may be in a child window, if it's a control in the "thick titlebar" area and we're currently full-screen.

            if newFirstResponderWindow != self, newFirstResponderWindow != currentFirstResponderWindow, currentEvent?.window != newFirstResponderWindow {

                var currentView: NSView? = responderView
                while currentView != nil {
                    if let currentView = currentView as? PopoverFirstResponderStealingSuppression, currentView.suppressFirstResponderWhenPopoverShows {
                        return false
                    }

                    currentView = currentView?.superview
                }
            }
        }

        return super.makeFirstResponder(responder)
    }
}

Answer 4

在设计要在表视图中使用的自定义控件时，我偶然发现了这个问题。

看来，至少在最新版本的Mac OS X中，您可以将表格发送到Popover（或那里的任何窃取焦点的视图）中tableView.refusesFirstResponder = true。

如果您这样做，弹出窗口将不再尝试窃取第一响应者。