Question

我有文字框和下拉，我的问题是我有供应商和国家两个下降，但它采取供应商下降值，它唯一的国家下降。（我显示数据库中的下拉数据）。任何人告诉我我哪里出错了

HTML：

<form name="welcomeDiv1" id="welcomeDiv1">

<select name="supplier" id="supplier" style="margin:122px 0 0 939px;background-color:#E8E8E8;width:100px;position: absolute;"> 
   <option value="">Select supplier</option>
<?php

$sqlsupplier=mysql_query("SELECT supplier_id  FROM supplier");


while($row=mysql_fetch_assoc($sqlsupplier))

{

    echo "<option value='" . $row['supplier_id'] . "'>" . $row['supplier_id'] . "</option>";
}  

   ?>


</select>


    <select id="country" name="country" style="margin:122px 0 0 511px;background-color:#E8E8E8;width:100px;position: absolute;" >
        <option value="">Select Country</option>
        <?php

            $query = "SELECT DISTINCT country  FROM globalnetwork";
            $result = mysql_query($query);
            while($row = mysql_fetch_array($result)){
                echo "<option value='" . $row['country'] . "'>" . $row['country'] . "</option>";
            }

        ?>
    </select>

</form>

  <img   src="/image/add-new.png" style="margin:116px 0 -5px 2659px;cursor:pointer;position: absolute;" class="billingadddet_button" >

的javascript

$(function() {
    $(".billingadddet_button").click(function() {

    var CPH_GridView1_billingmonthid = $("#CPH_GridView1_billingmonthid").val();
    var CPH_GridView1_clientid = $("#CPH_GridView1_clientid").val();
    var CPH_GridView1_clientname=  $("#CPH_GridView1_clientname").val();
    var CPH_GridView1_billingyear=  $("#CPH_GridView1_billingyear").val();
    var CPH_GridView1_billingmonth =  $("#CPH_GridView1_billingmonth").val();
    var CPH_GridView1_country =  $("#country").val();
    var CPH_GridView1_supplier =  $("#supplier").val();

    var dataString = 'CPH_GridView1_billingmonthid='+ CPH_GridView1_billingmonthid +'&CPH_GridView1_clientid='+CPH_GridView1_clientid+'&CPH_GridView1_clientname='+CPH_GridView1_clientname+'&CPH_GridView1_billingyear='+CPH_GridView1_billingyear+'&CPH_GridView1_billingmonth='+CPH_GridView1_billingmonth+'&CPH_GridView1_country='+CPH_GridView1_country+'&CPH_GridView1_supplier='+CPH_GridView1_supplier;


    if(CPH_GridView1_clientid=='')
    {
    alert("Please Enter Some Text");
    }
    else
    {
    $("#flash").show();
    $("#flash").fadeIn(400).html;

    $.ajax({
    type: "POST",
    url: "insertdetailed.php",
    data: dataString,
    cache: false,
    success: function(html){
    $("#display").after(html);

    window.location = '?action=billingdatainputandexportdetailedreport';
    $("#flash").hide();
    }
    });
    } return false;
    });
    });

insertdetailed.php

$billingmonthid = $_POST['CPH_GridView1_billingmonthid'];
if(isSet($_POST['CPH_GridView1_billingmonthid']))

{
$billingmonthid = $_POST['CPH_GridView1_billingmonthid'];
$clientid=$_POST['CPH_GridView1_clientid'];
$clientname=$_POST['CPH_GridView1_clientname'];
$billingyear=$_POST['CPH_GridView1_billingyear'];
$billingmonth=$_POST['CPH_GridView1_billingmonth'];
$country=$_POST['CPH_GridView1_country'];
$supplier=$_POST['CPH_GridView1_supplier'];

$sql_insert="insert into billingdetailedreport(billingmonthid,clientid,clientname,billingyear,billingmonth,supplier,country) values ('$billingmonthid','$clientid','$clientname','$billingyear','$billingmonth','$supplier','$country')";
//print "Here";
print $sql_insert;
mysql_query($sql_insert);

}

Answer 1

试试这个

$( "#country option:selected").val();

同样的Suplier

$( "#supplier option:selected").val();

我也可以建议使用$（“＃welcomeDiv1”）。serialize（）并在ajax请求中使用它

希望这会有所帮助。

如何在ajax中传递下拉值

1 个答案: