这是我的函数,它检索段落数组:
function first_paragraph() {
global $post, $posts;
$first_para = '';
ob_start();
ob_end_clean();
$post_content = $post->post_content;
$post_content = apply_filters('the_content', $post_content);
$output = preg_match_all('%(<p[^>]*>.*?</p>)%i', $post_content, $matches);
$first_para = $matches[0][0];
print_r($matches);
}
这导致以下数组:
(
[0] => Array
(
[0] => <p>I am not in any category.</p>
[1] => <p>Second paragraph.</p>
[2] => <p>Third paragraph</p>
[3] => <p>Fourth paragraph</p>
)
[1] => Array
(
[0] => <p>I am not in any category.</p>
[1] => <p>Second paragraph.</p>
[2] => <p>Third paragraph</p>
[3] => <p>Fourth paragraph</p>
)
)
是否可以只遍历其中一个阵列,而不是两者?我是PHP的新手,所以任何指导或资源都会受到赞赏。
PS:我不确定为什么preg_match_all会返回两个数组,也许有人可以对此有所了解?
答案 0 :(得分:0)
是的,你可以这样做:
foreach ($matches as $key => $paragraph){
if( $key == 0 ) {
// Here you can use the value of $paragraph
// $paragraph[0] contains "<p>I am not in any category.</p>"
// $paragraph[1] contains "<p>Second paragraph.</p>"
etc...
}
}
答案 1 :(得分:0)
我认为您的帖子数据看起来像是:
<p>I am not in any category.</p>
<p>Second paragraph.</p>
<p>Third paragraph</p>
<p>Fourth paragraph</p>
因此,根据PHP.net,默认情况下$ flags参数等于 PREG_PATTERN_ORDER ,因此“Orders结果使得 $ matches [0]是一个完整模式匹配的数组< / strong>,$ matches [1]是由第一个带括号的子模式匹配的字符串数组,依此类推。“
所以,例如,如果你将你的模式改为%<p[^>]*>(.*?)</p>%i
,你会得到类似的东西:
(
[0] => Array
(
[0] => <p>I am not in any category.</p>
[1] => <p>Second paragraph.</p>
[2] => <p>Third paragraph</p>
[3] => <p>Fourth paragraph</p>
)
[1] => Array
(
[0] => I am not in any category.
[1] => Second paragraph.
[2] => Third paragraph
[3] => Fourth paragraph
)
)
因此,如果只需要子模式,则必须仅循环抛出子模式结果数组。我假设在你的情况下它将是第二个($ matches [1])。
在PHP.net上阅读有关preg_match_all的更多信息:http://php.net/manual/en/function.preg-match-all.php