Question

我有以下程序;

import string
import random

randomgrid = []
codewordgrid = []
codedmessage = []
letters = "ABCDEF" 
markletters = "MARK" 


message = input("<<<ENTER MESSAGE TO BE ENCODED>>>\n").upper().replace(' ', '')
print ('<<<MESSAGE>>>\n', message)


newlist = list(string.ascii_uppercase + string.digits)
random.shuffle(newlist)


print ('<<<ORIGINAL RANDOM GRID>>>')

for x in range(0,len(newlist),6):
    randomgrid.append(list(newlist[x:x+6]))


for letter in message: 
    for y, vector in enumerate(randomgrid): 
        for s, member in enumerate(vector): 
            if letter == member:
                codedmessage.append([letters[s], letters[y]])


for item in randomgrid: print(item)

for u in range(0,len(newlist),4):
    codewordgrid.append(codedmessage)


print ('<<<CODED MESSAGE>>>\n', codedmessage)
print ('<<<CODEWORD GRID>>>', codewordgrid)
for item in codewordgrid: print(item)

到目前为止一切正常，除了我有一个问题。当打印编码字网格时，它会一次又一次地重复。我想限制代码字网格的大小，以便使用代码字MARK（在标记中）填充4x4网格，而不是一遍又一遍地重复，我不确定如何做到这一点，所以请帮助。

实际输出：

<<<CODEWORD GRID>>> [[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']], [['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]
[['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B'], ['F', 'B']]

实际上它应该使用代码字“Mark”

拟合到4x4网格中

由于

Answer 1

创建codewordgrid时：

for u in range(0,len(newlist),4):
    codewordgrid.append(codedmessage)

您以len(wordlist) == 36：4为步骤迭代[0, 4, 8, 12, 16, 20, 24, 28, 32]。这会为您提供8行，每行包含codedmessage。

如果你想用markletters 4次填充它，就这样做：

codewordgrid = [list(markletters) for _ in range(4)]

得到

codewordgrid = [['M', 'A', 'R', 'K'], 
                ['M', 'A', 'R', 'K'], 
                ['M', 'A', 'R', 'K'], 
                ['M', 'A', 'R', 'K']]

Python密码程序 - 限制列表大小

1 个答案: