Question

我想要雅虎！天气API，温度为摄氏度。

我在请求中添加了&u=c，但它仍然以华氏度返回数据。

这是我正在使用的网址：

http://query.yahooapis.com/v1/public/yql?q=select%20item%20from%20weather.forecast%20where%20location=%22LEXX0003%22&format=json&u=c

回复：

{"query":{"count":1,"created":"2014-01-13T13:06:43Z","lang":"en-US","results":{"channel":{"item":{"title":"Conditions for Beirut, LE at 1:59 pm EET","lat":"33.82","long":"35.48","link":"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html","pubDate":"Mon, 13 Jan 2014 1:59 pm EET","condition":{"code":"30","date":"Mon, 13 Jan 2014 1:59 pm EET","temp":"64","text":"Partly Cloudy"},"description":"\n<img src=\"http://l.yimg.com/a/i/us/we/52/30.gif\"/><br />\n<b>Current Conditions:</b><br />\nPartly Cloudy, 64 F<BR />\n<BR /><b>Forecast:</b><BR />\nMon - Partly Cloudy. High: 64 Low: 55<br />\nTue - Cloudy. High: 66 Low: 56<br />\nWed - Mostly Sunny. High: 68 Low: 58<br />\nThu - Sunny. High: 70 Low: 60<br />\nFri - Scattered Showers. High: 65 Low: 57<br />\n<br />\n<a href=\"http://us.rd.yahoo.com/dailynews/rss/weather/Beirut__LE/*http://weather.yahoo.com/forecast/LEXX0003_f.html\">Full Forecast at Yahoo! Weather</a><BR/><BR/>\n(provided by <a href=\"http://www.weather.com\" >The Weather Channel</a>)<br/>\n","forecast":[{"code":"30","date":"13 Jan 2014","day":"Mon","high":"64","low":"55","text":"Partly Cloudy"},{"code":"26","date":"14 Jan 2014","day":"Tue","high":"66","low":"56","text":"Cloudy"},{"code":"34","date":"15 Jan 2014","day":"Wed","high":"68","low":"58","text":"Mostly Sunny"},{"code":"32","date":"16 Jan 2014","day":"Thu","high":"70","low":"60","text":"Sunny"},{"code":"39","date":"17 Jan 2014","day":"Fri","high":"65","low":"57","text":"Scattered Showers"}],"guid":{"isPermaLink":"false","content":"LEXX0003_2014_01_17_7_00_EET"}}}}}}`

有什么想法吗？

Answer 1

迟到总比不上......

var locationQuery = escape("select item from weather.forecast where woeid in (select woeid from geo.places where text='GB-LND') and u='c'"),
    locationUrl = "http://query.yahooapis.com/v1/public/yql?q=" + locationQuery + "&format=json&callback=?";

如果你分手，它会更容易阅读。你我们非常接近，只需要u = c作为查询的一部分，而不是在网址的末尾。

Answer 2

我使用了yql

maxlength

它在Celsius中的效果很好。我将“LEXX0003”更改为该区域的真实WOEID，似乎已经有效。

Answer 3

每当我必须在Celsius中调用我想要的温度时，我只使用了一个简单的转换函数：

function FtoC(temp) {return Math.round((temp - 32) / (9 / 5));}

然后，我想在华氏和摄氏之间切换。如果您想要使用的只是Celsius，那么从Yahoo调用Celsius JSON元素可能会更好。

Answer 4

你可以试试这个：

YQL查询：

select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="jiangmen,cn") and u="c"

端点：

https://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20weather.forecast%20where%20woeid%20in%20(select%20woeid%20from%20geo.places(1)%20where%20text%3D%22jiangmen%2Ccn%22)%20and%20u%3D%22c%22&format=json&env=store%3A%2F%2Fdatatables.org%2Falltableswithkeys

刚刚尝试时的这项工作

Answer 5

只需执行此操作，确保它可以工作

在YQL查询末尾添加-> {和u =“ c” }

例如：

YQL查询

select * from weather.forecast where woeid in (select woeid from geo.places(1) where text="greenland") and u="c"

返回Yahoo!使用YQL以Celsius为天气API数据

5 个答案: