所以我对编程完全不熟悉;我已经在这里阅读了许多类似的问题和各自的答案,花了更多的时间,而不是尝试尝试不同的方法来解决我的问题,但我似乎无法找到问题所在。无论如何,这是我的代码:
public struct City
{
public string cityName { get; set; }
public float cityTemp { get; set; }
}
class Program
{
static void Main(string[] args)
{
var cityList = new List<City>();
cityList.Add(new City
{
cityName = "Stockholm",
cityTemp = 22.65f
});
Console.WriteLine("List: ");
Console.WriteLine(cityList);
Console.ReadKey();
}
}
如何使列表存储我的结构以及如何正确显示列表? 编辑:我知道我需要使用foreach,这段代码只是我问题的准确代表。
答案 0 :(得分:2)
你想要这样的东西:
public struct City
{
public string cityName { get; set; }
public float cityTemp { get; set; }
}
class Program
{
static void Main(string[] args)
{
var cityList = new List<City>();
cityList.Add(new City
{
cityName = "Stockholm",
cityTemp = 22.65f
});
cityList.Add(new City
{
cityName = "London",
cityTemp = 25.24f
});
Console.WriteLine("List: ");
foreach (var city in cityList)
{
Console.WriteLine(string.Format("City: {0} is currently: {1}oC", city.cityName, city.cityTemp);
}
Console.ReadKey();
}
}
您还可以通过覆盖ToString()
来使您的城市输出成为明智的回应:
public struct City
{
public string cityName { get; set; }
public float cityTemp { get; set; }
public override string ToString()
{
return String.Format("City: {0} is currently: {1}oC", cityName, cityTemp);
}
}
那么你可以:
class Program
{
static void Main(string[] args)
{
var cityList = new List<City>();
cityList.Add(new City
{
cityName = "Stockholm",
cityTemp = 22.65f
});
cityList.Add(new City
{
cityName = "London",
cityTemp = 25.24f
});
Console.WriteLine("List: ");
foreach (var city in cityList)
{
Console.WriteLine(city);
}
Console.ReadKey();
}
}
答案 1 :(得分:1)
列表 存储您的结构。至于显示它们,这不是魔法。你必须遍历列表并显示每个列表。
public struct City
{
public string cityName { get; set; }
public float cityTemp { get; set; }
public override string ToString()
{
return String.Format("{0} {1}", cityName, cityTemp);
}
}
public void DisplayAll(IEnumerable<City> cities)
{
foreach (var city in cities)
Console.WriteLine(city);
}
答案 2 :(得分:0)
您需要遍历城市列表以显示它们:
Console.WriteLine("List: ");
foreach(var city in cityList)
{
Console.WriteLine(city.cityName + " " + city.cityTemp);
}