Question

我试图通过json将数据发布到服务器中。假设我的xib中只有一个名为username的字段。现在我将这些数据发布到服务器中。我写了这段代码 NSString * uname = txt_name.text;

NSMutableURLRequest *request =[[NSMutableURLRequest alloc] initWithURL:
 [NSURL URLWithString:@"http://mypath/index.php?params=123"]];

[request setHTTPMethod:@"POST"];

// NSString *postString = @"Email=me@test.com";

[request setValue:[NSString
                   stringWithFormat:@"%d", [uname length]]
forHTTPHeaderField:@"Content-length"];

[request setHTTPBody:[uname
                      dataUsingEncoding:NSUTF8StringEncoding]];

[[NSURLConnection alloc]
 initWithRequest:request delegate:self];

NSLog(@"text",uname);

但我不知道数据是否发布。我想将输入数据发布到Xcode的控制台中，但没有显示任何内容。是什么原因..？什么是错的......？

Answer 1

您需要以下请求：

NSDictionary *dataDict = @{@"uname": <YOUR_UNAME>};

NSData *postData = [NSJSONSerialization dataWithJSONObject:dataDict options:0 error:nil];

NSMutableURLRequest *request =[[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:@"http://mypath/index.php?params=123"]];

[request setHTTPMethod:@"POST"];
[request setHTTPBody:postData];
[request setValue:[NSString stringWithFormat:@"%d",postData.length] forHTTPHeaderField:@"Content-Length"];
[request setValue:@"application/json; charset=utf-8" forHTTPHeaderField:@"Content-Type"];

确保服务器已使用您的数据

- (void) connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response
{
    NSHTTPURLResponse *httpResponse = (NSHTTPURLResponse *)response;
    NSInteger statusCode = httpResponse.statusCode;
    ...........
}

如果成功，您将获得 statusCode = 200。

Answer 2

NSString *string= [NSString stringWithFormat:@"your Url.php?&Username=%@",username];
        NSLog(@"%@",string);
        NSURL *url = [NSURL URLWithString:string];
        NSMutableURLRequest *request = [NSMutableURLRequest requestWithURL:url];
        [request setHTTPMethod:@"POST"];

        NSURLResponse *response;
        NSError *err;
        NSData *responseData = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&err];
        NSLog(@"responseData: %@", responseData);
        NSString *str = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding];
        NSLog(@"responseData: %@", str);
        NSString *str1 = @"1";
        if ([str isEqualToString:str1 ])
        {

            UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Successfully" message:@"" delegate:nil cancelButtonTitle:@"Ok" otherButtonTitles:nil, nil];
            [alert show];
        }
        else
        {
            UIAlertView *alert = [[UIAlertView alloc]initWithTitle:@"Try Again" message:@"" delegate:self cancelButtonTitle:@"Try Later" otherButtonTitles:@"Call", nil];
            alert.tag = 1;
            [alert show];
        }

不需要使用JSON就可以在没有JSON的情况下实现这一点!!!

如何通过iOS中的json发布数据

2 个答案: