Question

如何将多个元素放入byte[]？我有以下3个元素：1）String data，2）String status和3）HashMap<String,String> headers，需要作为字节数组传递给setContent(byte[] data)。以下是我想使用前面3个参数作为statusResult.setContent()输入的代码：

public void onSuccess(ClientResponse clientResponse){
      String data=clientResponse.getMessage();
      String status=String.valueOf(clientResponse.getStatus());
      HashMap<String,String> headers=clientResponse.getHeaders();

    // Now StatusResult is a class where we need to pass all this data,having only getters and
   //  setters for Content,so here in the next line i need to pass data,status and headers as 
  //   a byte[] to setContent.

       statusResult.setContent(byte[]);
}

有人可以帮我解决这个问题吗？

Answer 1

这是粗略的序列化。我建议如下：

创建封装三个元素的类。
确保课程implements serializable界面。
根据需要使用以下代码[取自 this post] 创建字节数组，并从字节数组中读取对象（虽然你没有指明要求，但为了完整性需要提及）

ByteArrayOutputStream bos = new ByteArrayOutputStream();
ObjectOutput out = null;
try {
  //Assuming that bos is the object to be seriaized
  out = new ObjectOutputStream(bos);   
  out.writeObject(yourObject);
  byte[] yourBytes = bos.toByteArray();
  ...
} finally {
  try {
    if (out != null) {
      out.close();
    }
  } catch (IOException ex) {
    // ignore close exception
  }
  try {
    bos.close();
  } catch (IOException ex) {
    // ignore close exception
  }
}
//Create object from bytes:

ByteArrayInputStream bis = new ByteArrayInputStream(yourBytes);
ObjectInput in = null;
try {
  in = new ObjectInputStream(bis);
  Object o = in.readObject(); 
  ...
} finally {
  try {
    bis.close();
  } catch (IOException ex) {
    // ignore close exception
  }
  try {
    if (in != null) {
      in.close();
    }
  } catch (IOException ex) {
    // ignore close exception
  }
}

如何在java中将多个元素放入byte []

1 个答案: