Question

我有一个String数组

String student [] = {"BAT4M0ABBB4M0ABOH4M0CCHI4U0AENG4U0DMDM4U0B"}

我需要为每7个字符拆分一次。它应该是这样的：

String student {
"BAT4M0A",
"BBB4M0A",
"BOH4M0C",
"CHI4U0A",
"ENG4U0D",
"MDM4U0B"
}

到目前为止，这是我的代码。

       for (int i=0; i<= data.length; i++)
        {
          student= data[i].split(","); //data is a file of 1000 lines that is being read
          if (student [2].equals(sN)) //student is a line in the each file that has been  split into 11 parts
        {
            String timetable[]= student[9].split("(?<=\\G.......)");
            System.out.println (timetable);
            break;
        }

Answer 1

你可以做到

String[] array = student[0].split("(?<=\\G.{7})");

\G是与上一个匹配项匹配的元字符，因此(?<=\\G.{7})匹配空字符串后跟任意7个字符

IDEOne Demo

Answer 2

您可以使用guava Splitter：

String str = "BAT4M0ABBB4M0ABOH4M0CCHI4U0AENG4U0DMDM4U0B"
Iterable<String> parts = Splitter.fixedLength(7).split(str);

Answer 3

使用string.substring（i，j）; 我是第一个角色，j是最后一个角色。创建一个遍历整个字符串的循环

很容易

如何在没有空格的情况下将字符串拆分为java中的多个单词？

3 个答案: