如何在html表中显示数据库中users表中的所有用户？ 我必须在html表中显示所有用户，并且可以使用复选框选择每个用户。然后从数据库中删除所选用户。 我正在使用mvc技术，我有一个页面“DeleteUser”，只包含html，控制器和公共文件。
查看/ DeleteUser.php 包含：
<form method="post" action="../public/deleteUser.php">
<table>
<tr>
<td>#</td>
<td>Username</td>
<td>First name</td>
<td>Last name</td>
<td>City</td>
<td>Gender</td>
<td>E-mail</td>
<td>Check</td>
</tr>
<tr>
<td><input type="submit" name="submit-deleteuser" value="Delete user"/></td>
</tr>
</table>
</form>
public / deleteUser.php 包含：
$controller = new DeleteUserController();
$view = $controller->invoke();
$view->render();
Controller / DeleteUserController.php 中的 invoke（）方法包含：
class DeleteUserController {
public $user;
public $users;
public $userRepository;
public $view;
public function __construct() {
$username = $_SESSION['username'];
$this->userRepository = new UserRepository();
$this->user = $this->userRepository->findByUsername($username);
$this->users = array();
$this->view = new View('DeleteUser');
$db = Database::getInstance();
}
public function listUsers() {
$this->users = $this->userRepository->fetchAll();
foreach($this->users as $u) {
$str = "<tr>
<td><?php $u->getId() ?></td>
</tr>";
}
}
public function deleteUsers() {
if(isset($_POST['submit-deleteuser'])) {
$del_id = $_POST['users'];
foreach($del_id as $value) {
$value->delete();
}
}
}
public function work() {
$this->listUsers();
$this->deleteUsers();
}
public function invoke() {
$this->work();
$this->view->setData('user', $this->user);
return $this->view;
}
如果我不必使用mvc，我会这样做：
<table>
<tr>
<td>#</td>
<td>Username</td>
<td>Fisrt name</td>
<td>Last name</td>
<td>City</td>
<td>Gender</td>
<td>E-mail</td>
<td>Check</td>
</tr>
<?php
$utente = $_SESSION['username'];
$query = "SELECT * FROM users ORDER BY id";
$result = mysql_query($query);
while($row = mysql_fetch_array($result)) {
echo "<tr>
<td>$row[id]</td>
<td>$row[username]</td>
<td>$row[fisrt_name]</td>
<td>$row[last_name]</td>
<td>$row[city]</td>
<td>$row[gender]</td>
<td>$row[email]</td>
<td><input type=\"checkbox\" name=\"users[]\" value=\"" .$row['id']. "\"></td>
</tr>";
}
}
?>
<tr>
<td colspan="9"><input type="submit" name="submit-deleteuser" value="Delete users"/></td>
</tr>
</table>
但现在我不知道该怎么办。两个方法 listUsers（）和 deleteUsers（）是错误的，不知道如何完成它们或纠正它们。
首先它很简单，我把PHP代码显示在我想要的html标签中（<table>...</table>），但现在呢？
我不知道如何处理这件事。
给我建议？谢谢:)）
fetchAll（）是：
public function fetchAll(){
$db = Database::getInstance();
$stmt = $db->prepare("SELECT * FROM `users`");
$stmt->execute();
$users = array();
while($result = $stmt->fetch()) {
$users[] = User::load($result);
}
return $users;
}
答案 0 :(得分：1)
尝试使用MVC模式是令人钦佩的，但在这种情况下有一点点:)。缺少的是控制器动作的概念。
也许尝试重构一下这样的代码：
目录结构
<强> 1。从与数据库交互的用户模型开始
class UsersModel {
public function fetchAll() {
$result = array();
// Build SELECT query, fetch all users from db., and store in $result
// ...
return $result;
}
public function deleteMany(array $ids) {
$result = array();
// Build DELETE query, execute it, and store the number of affected records in $result
// ...
return $result;
}
}
<强> 2。创建UsersController而不是DeleteUserController。创建两个方法：listUsersAction和deleteUsersAction。
class UsersController {
public function listUsersAction() {
$model = new UsersModel();
$data = $model->fetchAll();
return new View(
'users/list',
$data
);
}
public function deleteUsersAction() {
// This is simplistic, but the idea is to get the required input from the request (and actually validate it!)
// Also see the users/list template further down
$ids = $_POST['user_ids'];
$model = new UsersModel();
$numRecords = $model->deleteMany($ids);
return new View(
'users/delete',
array('deleted_records' => $numRecords)
);
}
}
第3。我们的View类应存储模板名称和视图数据，并能够呈现模板
class View {
public static $viewDirectory;
public $template;
public $data = array();
public function __construct($template, $data) {
if (!View::$viewDirectory) {
View::$viewDirectory = dirname(__FILE__) . '/views/';
}
$this->template = $template;
$this->data = $data;
}
public function render() {
// Make the data available in the template
$data = $this->data;
// Include the template.
require(realpath(View::$viewDirectory . $this->template . '.tpl.php'));
}
}
<强> 4。用户/列表模板可能看起来像这样
// views/users/list.tpl.php
<form action="/users.php?action=delete" method="post">
<?php foreach ($data as $user): ?>
<div>
<input type="checkbox" name="user_ids[<?= $user['id'] ?>]" value="1"/>
<?= $user['username'] ?>
</div>
<?php endforeach; ?>
</form>
<强> 5。在users.php中将所有内容联系在一起
<?php
// users.php
// (include all previously defined classes here)
// We'll want to include a HTML header of some sort:
include("views/header.tpl.php");
/**********
* Poor man's routing; valid urls:
* /users.php?action=listUsers
* /users.php?action=deleteUsers with POST data
*/
// Determine the action from the GET parameter. If no action is set, the default action is listUsers
//$action = (array_key_exists('action', $_GET) ? $_GET['action'] : 'listUsers');
// Equivalent of:
if (array_key_exists('action', $_GET)) {
$action = $_GET['action'];
} else {
$action = 'listUsers';
}
//--
$actionMethod = $action . 'Action';
$controller = new UsersController();
if (method_exists($controller, $actionMethod)) {
$view = $controller->$actionMethod();
$view->render();
} else {
echo "<div class='error'>The action '$action' is invalid for the Users controller.'</div>";
}
// We'll want to include a footer as well:
include("views/footer.tpl.php");
?>