Question

好的..我一直在盯着这段代码而我在代码中看不到错误。我的代码连接到数据库正常，我的控制台日志显示我的结果

{ id: 7,
name: 'Tap\'s',
quicklist: 'Y',
message: 'Welcome..enjoy one of our many craft brews!',
fbflag: 'Y',
facebookurl: 'https://www.facebook.com/TapsPourhouseMooresville',
twflag: 'Y',
twitterurl: 'https://twitter.com/TapsPourhouse',
contactflag: 'Y',
contactemail: 'info@blazingpoint.com',
eventsflag: 'Y',
loyaltyflag: 'Y',
loyaltyclub: 'TAPped In',
loyaltymessage: 'Become a member of the TAPped In Club in order to receive special offers and to stay informed on upcoming events and exclusive offers!',
locdescription: 'Table 10' }

这是我想要归还的东西，但我一直在努力 TypeError：object不是函数参考以下评论的行。

exports.get_site_setup = function (callback) {
var dbc;

async.waterfall([
    // get a connection
    function (cb) {
//           if (!name)
//               cb(backhelp.missing_data("site name"));
//           else
              db.db(cb);
    },

    function (dbclient, cb) {
        dbc = dbclient;
        dbc.query("select s.ID as id, s.NAME as name, s.QUICK_LIST_ENABLED as quicklist, s.MESSAGE as message, s.FBFLAG as fbflag, "+
                "s.FACEBOOKURL as facebookurl, s.TWFLAG as twflag, s.TWITTERURL as twitterurl, "+
                "s.CONTACTFLAG as contactflag, s.CONTACTEMAIL as contactemail, s.EVENTSFLAG as eventsflag, "+
                "s.LOYALTYFLAG as loyaltyflag, s.LOYALTYCLUB as loyaltyclub, s.LOYALTYMESSAGE as loyaltymessage, l.LOCDESC locdescription "+
                "from COMPANIES as c "+
                "left join SITES as s on c.ID = s.COMPANY_ID "+
                "left join LOCATION as l on s.ID = l.SITE_ID "+
                "where c.ID = 7 and s.ID = 7 and l.ID = 8",
                cb);
    }

],
function (err, results) {
    if (dbc) {dbc.end();}
    if (err) {
       callback(err);
    } else if (!results || results.length === 0) {
       // callback(backhelp.no_such_site());
    } else {
        callback(null, results[0]); //  <-- Error on this line
        console.log(results[0]);
    }
});
};

Answer 1

如果你查看瀑布的文档，你会看到按照数组的顺序调用回调函数，并且一旦处理了数组的所有元素，就会调用最终函数（错误，结果）。

https://github.com/caolan/async#waterfall

所以在你的第一次回调中

 function (cb) {
//           if (!name)
//               cb(backhelp.missing_data("site name"));
//           else
              db.db(cb);
    },

当你引用db.db（cb）;是调用cb（null，dbclient，cb）的函数转到数组中指定的下一个函数吗？

然后在发生dbc.query的第二个函数中，您需要确保查询调用cb（null，expected result）;

null指示瀑布没有错误并继续。

此外，您的结果变量可能是字符串而不是数组。请检查一下。如果它是一个字符串，那么这个测试就会通过（可能是你的问题。

} else if (!results || results.length === 0) {

Node.js错误TypeError：object不是回调函数

1 个答案: