Question

我想链接到具有上传者名称的上传者列的表。

<a href="?uploader=MM_Username" class="login"><?php echo $_SESSION['MM_Username'];?></a>

<?php 
$subQ2 = ''; 
if(isset($_GET['uploader']) && $_GET['uploader']!='')
{
     $subQ2 = ' WHERE uploader="'.mysql_real_escape_string(str_replace('_', '', $_GET['uploader'])).'"';     
}

function uploader()
{
    if(isset($_GET['uploader']) && $_GET['uploader']!='')
    {
        return $_GET['uploader'];
    }
    else return "uploader";
}

$query_Form = "SELECT * FROM docus".$subQ2.' ORDER BY ID DESC';
$Form = mysql_query($query_Form, $dbconnection) or die(mysql_error());
$row_Form = mysql_fetch_assoc($Form);
$totalRows_Form = mysql_num_rows($Form);
?>

我正在尝试从视频教程中学习php和sql，所以这可能听起来像一个愚蠢的问题。

任何帮助都是非常苛刻的

Answer 1

试试此代码

<?php 
function uploader()
{
    global $dbconnection;

    $return = array('data' => null, 'data_count' => 0);

    if(!empty($_GET['uploader']))
    {
         $data = mysql_real_escape_string(str_replace('_', '', $_GET['uploader']));

         $query_Form = 'SELECT * FROM docus  WHERE uploader="'.trim($data).'" ORDER BY ID DESC';

         $Form = mysql_query($query_Form, $dbconnection) or die(mysql_error());
         $return['data'] = mysql_fetch_assoc($Form);
         $return['data_count'] = mysql_num_rows($Form);
    }

    return $return;
}

$total = upload();

// $row_Form - is now $total['data];
// $totalRows_Form - is now $total['data_count];
?>

链接到包含列变量的表

1 个答案: