Question

我最近转移到Android Asynchronous Http Client Library以便更快地移动数据。

我想从旧状态和新状态移动我的代码。以下是我以前获取数据的方式：

public class loadSomeStuff extends AsyncTask<String, Integer, String> {
        @Override
        protected String doInBackground(String... params) {
            // TODO Auto-generated method stub
            InputStream isr = null;
            String result = "";
            String url;
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httpost;
            HttpResponse resposne;
            HttpEntity entity;
            BufferedReader reader;
            StringBuilder sb;
            String line = null;

            try {
                url = "Secret";
                httpost = new HttpPost(url);
                resposne = httpclient.execute(httpost);
                entity = resposne.getEntity();
                isr = entity.getContent();
                reader = new BufferedReader(
                        new InputStreamReader(isr, "UTF-8"), 8);
                sb = new StringBuilder();
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
                isr.close();
                result = sb.toString();

                JSONArray jArray = new JSONArray(result);
                for (int i = 0; i < jArray.length(); i++) {
                    JSONObject json = jArray.getJSONObject(i);
                    //filldatabase///
            } catch (Exception e) {
                e.printStackTrace();
            }
            return result;
        }

现在我该怎么做才能使用这个库？谢谢！

Answer 1

请按照文档中的示例进行操作：

AsyncHttpClient client = new AsyncHttpClient();
client.get("http://your/url/here/", new AsyncHttpResponseHandler() {
    @Override
    public void onSuccess(String response) {
        JSONArray jarr = new JSONArray(response);
        for(int i = 0; i < jarr.length(); ++i) {
            JSONObject jobj = jarr.getJSONObject(i);
            // do your things...
        }
    }
});

您不再需要AsyncTask，请将代码替换为new loadSomeStuff().start()并删除loadSomeStuff类。

Answer 2

小心使用此库，因为您无法在AsyncTask中使用它。我猜它已经使用了这个帖子。
如果JSON上没有任何内容，那可能是因为数据尚未返回。因此，在执行解析作业之前，必须等待util返回数据。

我有使用此库的经验。我认为这个库适用于某些回调并不重要的情况。例如，您不必等待数据返回并解析它。

也许你可以尝试这个（不推荐）：

AsyncHttpClient client = new AsyncHttpClient();
client.get("url", new AsyncHttpResponseHandler() {
@Override
public void onSuccess(String response) {
    //Check the data return
    while(response.length==0)
    {
        Thread.sleep(100);// Waiting for data return
    }
    //Parsing data
    JSONArray jarr = new JSONArray(response);
    for(int i = 0; i < jarr.length(); ++i) {
        JSONObject jobj = jarr.getJSONObject(i);
        ...
    }
}

}）;

以下是您旧代码的一些建议:) *分隔http帖子和JSON。把它们都放在一个班级里。 这样做可以使您的代码更简短，也可以重复使用。这就是我的意思：

public class Util {

public String doPost() {
    InputStream isr = null;
    String result = "";
    String url;
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httpost;
    HttpResponse resposne;
    HttpEntity entity;
    BufferedReader reader;
    StringBuilder sb;
    String line = null;

    try {
           url = "Secret";
           httpost = new HttpPost(url);
           resposne = httpclient.execute(httpost);
           entity = resposne.getEntity();
           isr = entity.getContent();
           reader = new BufferedReader(
                    new InputStreamReader(isr, "UTF-8"), 8);
                    sb = new StringBuilder();
                    while ((line = reader.readLine()) != null) {
                        sb.append(line + "\n");
                    }
                    isr.close();
                    result = sb.toString();

                    //Remove JSON
                } catch (Exception e) {
                    e.printStackTrace();
    }
    return result;
}

public parsindData(String result)
{
    JSONArray jArray = new JSONArray(result);
    for (int i = 0; i < jArray.length(); i++) {
    JSONObject json = jArray.getJSONObject(i);
    //filldatabase///
}

}

将它们用作对象：

// AsyncTask doInBackground

Util util=new Util();
String getCallBack=util.doPost();
if(getCallBack.length!=0)
{
    util.parsingData(getCallBack);
}

在“Android异步Http客户端库”中获取JSON

2 个答案: