Question

我收到错误*您的SQL语法出错了;检查与MySQL服务器版本对应的手册，以便在尝试更新和发送电子邮件时，在第1行*的“[0]”附近使用正确的语法。

$updatelist = explode(",",$Limited);
print_r($updatelist); // echos Array ( [0] => samplemail@gmail.com [1] => samplemal@yahoo.com [2] => ) 

$totalupdates = count($updatelist)-1;
for ($y = 0; $y < $totalupdates; $y++)
{
  $updatemail = "UPDATE tblusers SET date= '$date' WHERE Email = 'updatelist[$y]'";
  $updatefree = mysql_query($updatemail);

  echo $updatemail;

}

$ updatelist [$ y]有什么问题？它应该通过$ updatelist [0]循环到$ updatelist [1]吗？

Answer 1

更改$updatelist[$y]而不是updatelist[$y]

Answer 2

我认为问题在于：

$updatemail = "UPDATE tblusers SET date= '$date' WHERE Email = 'updatelist[$y]'";

试试这个：

$updatemail = "UPDATE tblusers SET date = '$date' WHERE Email = '$updatelist[$y]'";

Answer 3

试试这段代码：

$updatelist = explode(",",$Limited);
print_r($updatelist); // echos Array ( [0] => samplemail@gmail.com [1] => samplemal@yahoo.com [2] => ) 
$totalupdates = count($updatelist)-1;
foreach ($updateList as $key=>$val)
{
     $updatemail = "UPDATE tblusers SET date= '$date' WHERE Email = '".$val."'";
     $updatefree = mysql_query($updatemail);
}
 echo $updatemail;

Answer 4

尝试：

  $updatemail = "UPDATE tblusers SET date= '".$date."' WHERE Email = '".$updatelist[$y]."'";

数组语法错误PHP

4 个答案: