我正在尝试实现我自己的wsgiref版本用于学习目的,我最终在这里:
from wsgiref.simple_server import make_server
class DemoApp():
def __init__(self, environ, start_response):
self.environ = environ
self.start = start_response
def __iter__(self, status):
self.status = '200 OK'
response_headers = [('Content-type','text/plain')]
self.start(status, response_headers)
return ["Hello World"]
if __name__ == '__main__':
httpd = make_server('', 1000, DemoApp)
print("Serving on port 1000")
httpd.serve_forever()
当我转到端口1000时,我收到属性错误。
AttributeError: 'NoneType' object has no attribute 'split'
我在哪里留下错误?
堆栈跟踪:
Serving on port 1000
Traceback (most recent call last):
File "C:\Python27\lib\wsgiref\handlers.py", line 86, in run
self.finish_response()
File "C:\Python27\lib\wsgiref\handlers.py", line 131, in finish_response
self.close()
File "C:\Python27\lib\wsgiref\simple_server.py", line 33, in close
self.status.split(' ',1)[0], self.bytes_sent
AttributeError: 'NoneType' object has no attribute 'split'
127.0.0.1 - - [11/Jan/2014 12:40:09] "GET / HTTP/1.1" 500 59
Traceback (most recent call last):
File "C:\Python27\lib\SocketServer.py", line 295, in _handle_request_noblock
----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 54469)
self.process_request(request, client_address)
File "C:\Python27\lib\SocketServer.py", line 321, in process_request
self.finish_request(request, client_address)
File "C:\Python27\lib\SocketServer.py", line 334, in finish_request
self.RequestHandlerClass(request, client_address, self)
File "C:\Python27\lib\SocketServer.py", line 649, in __init__
self.handle()
File "C:\Python27\lib\wsgiref\simple_server.py", line 124, in handle
handler.run(self.server.get_app())
File "C:\Python27\lib\wsgiref\handlers.py", line 92, in run
self.close()
File "C:\Python27\lib\wsgiref\simple_server.py", line 33, in close
self.status.split(' ',1)[0], self.bytes_sent
AttributeError: 'NoneType' object has no attribute 'split'
答案 0 :(得分:9)
您应该将返回的正文编码为utf-8
return ["Hello World".encode("utf-8")]
此代码可以正常使用,我正在使用Python 3.3.3:
from wsgiref.simple_server import make_server
def app(env, start_response):
body = "Hello"
status = "200 OK"
headers = [("Content-Type", "text/plain; charset=utf-8")]
start_response(status, headers)
return [body.encode("utf-8")]
port = 9080
httpd = make_server("localhost", port, app)
print("Server started on port: ", port)
httpd.serve_forever()
答案 1 :(得分:5)
DemoApp
被调用;使用DemoApp.__init__
的返回值。
DemoApp.__init__
什么都不返回(你不能在构造函数中返回任何东西)。
尝试关注而不是DemoApp
类:
def DemoApp(environ, start_response):
response_headers = [('Content-type','text/plain')]
start_response('200 OK', response_headers)
return ["Hello World"]
使用课程(使用__call__
代替__iter__
):
from wsgiref.simple_server import make_server
class DemoApp:
def __call__(self, environ, start_response):
response_headers = [('Content-type','text/plain')]
start_response('200 OK', response_headers)
return ["Hello World"]
if __name__ == '__main__':
httpd = make_server('', 1000, DemoApp()) # Don't forget instantiate a class.
# ^^
print("Serving on port 1000")
httpd.serve_forever()
答案 2 :(得分:3)
这个怎么样,你需要yield
输出而不是返回它。
from wsgiref.simple_server import make_server
class DemoApp:
def __init__(self, environ, start_response):
self.environ = environ
self.start = start_response
def __iter__(self):
status = '200 OK'
response_headers = [('Content-type', 'text/plain')]
self.start(status, response_headers)
yield 'Hello world!'
if __name__ == '__main__':
httpd = make_server('', 1000, DemoApp)
print("Serving HTTP on port 1000...")
httpd.serve_forever()
答案 3 :(得分:0)
添加.encode("utf-8")
解决了我的问题Python 3.4.2
答案 4 :(得分:-1)
我有同样的问题。
我通过在dest.txt
中设置fs
来解决了这个问题。
Django 2.2