所以我写了一个小的Hangman游戏,但我没有CLUE为什么它不起作用。通常我会问一个问题来解决问题,但我根本不知道发生了什么以及为什么我遇到这个问题。没有错误。
以下是我的所有代码:
public static void main(String[] args) {
Scanner sc = new Scanner (System.in);
String mysteryGuess = "hello";
String userGuess = "";
int wrongGuesses;
System.out.println("Hello and welcome to Hang Man!");
loop:
for(;;){
String[] wordAsArray = convertToStringArray(mysteryGuess);
boolean[] guessed = new boolean[mysteryGuess.length()];
for (int i = 0; i<wordAsArray.length;i++)
if(wordAsArray[i] == userGuess)
guessed[i]=true;
System.out.println("Word so far:" + visibleWord(wordAsArray,guessed));
System.out.println("What is your guess?");
userGuess = sc.next();
if (guess(userGuess,wordAsArray,guessed) == true)
System.out.println("Correct");
else
System.out.println("Incorrect");
if (didWin(guessed)==true)
break loop;
}
}
//This method creates an array version of the parameter word
//For example, if word contained the data "hello", then this method
//would return {"h", "e", "l", "l", "o"}
//Parameters: word - a single word
//Returns: an array containing each letter in word
public static String[] convertToStringArray(String word) {
String [] pWord = new String [word.length()];
for (int i = 0; i<pWord.length; i++){
pWord[i] = word.substring(i,i+1);
}
return pWord;
}
//This method determines whether the player has won the game of HangMan
//Parameters: guessed - array of boolean values
//Returns: true - if every value in guessed is true
// false - if at least one value in guessed is false
public static boolean didWin(boolean[] guessed) {
boolean bGuess = true;
loop:
for (int i = 0; i<guessed.length;i++){
if(guessed[i]==false){
bGuess = false;
break loop;
}
}
return bGuess;
}
//This method determines what portion of the hidden word is visible
//For example, if the parameters are as follows:
// wordAsArray: {"h", "e", "l", "l", "o"}
// guessed: {true, false, false, false, true}
//Then the method should return "h???o"
//Parameters: wordAsArray - the individual letters to be guessed
// guessed - array of boolean values; a true value means the corresponding letter has been guessed
//Returns: A string representing how much of the word has been guessed (unguessed letters are represented by ?'s)
public static String visibleWord(String[] wordAsArray, boolean[] guessed) {
String visibleWord="";
for(int i = 0; i<wordAsArray.length;i++){
if (guessed[i] == true)
wordAsArray[i]=wordAsArray[i];
if (guessed[i] == false)
wordAsArray[i]="?";
}
for(int i = 0; i<wordAsArray.length;i++){
visibleWord=visibleWord+wordAsArray[i];
}
return visibleWord;
}
//This method checks to see if a player has made a successful guess in the game of Hang Man
//For example, if the parameters are as follows:
// letter: "e"
// wordAsArray: {"h", "e", "l", "l", "o"}
// guessed: {true, false, false, false, true}
//Then the guessed array would be changed to:
// guessed: {true, true, false, false, true}
//And the method would return false
//Parameters: letter - the letter that the user has just guessed
// wordAsArray - an array of individual letters that are to be guessed
// guessed - array of boolean values; a true value means the corresponding letter has been guessed
//Returns: true - if letter matches an unguessed letter in wordAsArray
// false - otherwise
public static boolean guess(String letter, String[] wordAsArray, boolean[] guessed) {
boolean appearsAtLeastOnce=false;
for(int i = 0; i<wordAsArray.length;i++)
if(letter.equalsIgnoreCase(wordAsArray[i])){
guessed[i] = true;
appearsAtLeastOnce=true;
}
return appearsAtLeastOnce;
}
}
因此,当你输入你的猜测,即使它是正确的,它会说它不正确,“到目前为止”这个词不会表明你弄错了。有人可以向我解释这里有什么问题吗?我确信这是一件我想念的简单事情,但我已经在这几个小时了。谢谢。
另外,我只是用“hello”进行测试。我希望输入各种字典单词列表。
答案 0 :(得分:3)
更改
if(wordAsArray[i] == userGuess)
到
if(wordAsArray[i].equals(userGuess)) //Replace .equals with .equalsIgnoreCase for case insensitive compare.
您正在比较字符串,而不是对象。因此==
无效。
希望这有帮助。
答案 1 :(得分:1)
您的行if(wordAsArray[i] == userGuess)
正在比较两个对象,看它们是否相等。在这种情况下,有两个String对象。此比较检查对象的引用是否相等(内存位置)。尽管字符串具有相同的值,但它们是两个不同的对象,因此具有两个不同的存储位置,这将使它们不相等。
您要做的是检查两个对象值是否相同。这可以通过使用String.equals()方法来完成:
if(wordAsArray[i].equals(userGuess))
通常,在处理原始数据类型(int,float,boolean,char ...)时,==
比较工作正常。但是,在处理对象时,您应该使用对象的equals()方法。
有关原始类型的更多信息:http://docs.oracle.com/javase/tutorial/java/nutsandbolts/datatypes.html
答案 2 :(得分:0)
我没有深入审核您的代码,但是您的代码存在一些问题(可能还有一些问题):
inside
false`定义了猜测loop, so every time the array is initialized to all
。==
用于字符串,这将无法使用,您应使用String.equals()
方法代替,为什么不使用char
s?java.lang.String
有toCharArray()
,返回代表每个字符的char[]
,因为char
是原始的,您可以在其上使用==
运算符。