Question

我通常有这样的数组

(int) 0 => abc,
(int) 1 => def,
(int) 2 => ghi

如果我使用json_encode，它将成为

["abc", "def", "ghi"]

这对jquery自动完成非常有用

$(function() {
    var availableTags = <?php echo json_encode($companyList); ?>;
    $("#CompanyName").autocomplete({
        source: availableTags,
        delay: 10
    });
});

但是现在，我需要更多数据，我看看jquery自动完成示例，数据必须看起来像这样

var company = [
  {
    value: "jquery",
    label: "jQuery",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  },
  {
    value: "jquery-ui",
    label: "jQuery UI",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  },
  {
    value: "sizzlejs",
    label: "Sizzle JS",
    name: "the write less, do more, JavaScript library",
    address: "jquery_32x32.png",
    city: "xxxxx",
  }
];

如何以json_encode（或任何其他方式）来改变像这样的PHP数组

array(
    (int) 0 => array(
        'Company' => array(
            'id' => '19',
            'group_id' => '1',
            'name' => 'Harts Harts',
            'address' => 'xxx NE xxxth Street',
            'city' => 'Shoreline',
            'state' => 'WA',
            'zip' => '98155',
            'country' => '',
        )
    ),
    (int) 1 => array(
        'Company' => array(
            'id' => '21',
            'group_id' => '1',
            'name' => 'Andy Robin',
            'address' => 'xxx xxxth Ave NE',
            'city' => 'Bellevue',
            'state' => 'WA',
            'zip' => '98004',
            'country' => '',
        )
    )
)

看起来像jquery自动完成源，因为如果我直接使用json_encode（$ company），它将成为对象，我不能将它用于自动完成。

这个数组将有大约2500个数据谢谢

Answer 1

$return_arr = array();

$company_arr = array(
    (int) 0 =>  array(
        'id' => '19',
        'group_id' => '1',
        'name' => 'Harts Harts',
        'address' => 'xxx NE xxxth Street',
        'city' => 'Shoreline',
        'state' => 'WA',
        'zip' => '98155',
        'country' => '',
    ),
    (int) 1 => array(
        'id' => '21',
        'group_id' => '1',
        'name' => 'Andy Robin',
        'address' => 'xxx xxxth Ave NE',
        'city' => 'Bellevue',
        'state' => 'WA',
        'zip' => '98004',
        'country' => '',
    )
);

foreach ($company_arr as &$company) {
    array_push($return_arr,$company);
}


echo json_encode($return_arr);

输出：

[{"id":"19","group_id":"1","name":"Harts Harts","address":"xxx NE xxxth Street","city":"Shoreline","state":"WA","zip":"98155","country":""},{"id":"21","group_id":"1","name":"Andy Robin","address":"xxx xxxth Ave NE","city":"Bellevue","state":"WA","zip":"98004","country":""}]

http://codepad.org/dQ8r52Eq

注意：要用于jquery自动填充，您需要在返回的value中添加label或json字段。您目前没有这些字段。

Answer 2

使用jQuery parseJSON方法来解析从PHP获得的json。

var obj = jQuery.parseJSON( 'json_string_here' );

Answer 3

api jquery-ui：autocomplete

阅读自动完成的api后：

$companyList = array();
foreach($companies as $company){
    array_push( $companyList, $company["Company"]["name"]);
}

返回：

["Harts Harts","Andy Robin"]

自动完成功能可以使用此计划旧数组或对象属性数组label和value，如下所示：

[{label:"Harts Harts",value:"Harts Harts"},{label:"Andy Robin",value:"Andy Robin"}]

如果您还有其他问题，请询问。

Json编码自动完成源

3 个答案: