我有一个不按预期保存数据库记录的更新方法。
基本上发生的事情是,arrange_id没有按照我预期的方法保存到时间表中。
从save!
之后的变量输出中我会认为arrange_id将保存在时间段表中。
任何人都可以告诉我为什么不是,我在这里做错了什么?
# PUT /arrangements/1
def update
success = false
@arrangement = Arrangement.find(params[:id])
# Remove arrangement id from old timeslot
old_timeslot = Timeslot.find(@arrangement.timeslot_id)
old_timeslot.arrangement_id = nil
# Save arrangement id to new timeslot
new_timeslot = Timeslot.find(@arrangement.timeslot_id)
new_timeslot.arrangement_id = @arrangement.id
p "old_timeslot = #{old_timeslot.inspect}"
p "new_timeslot = #{new_timeslot.inspect}"
old_timeslot.save!
new_timeslot.save!
p "after save old_timeslot = #{old_timeslot.inspect}"
p "after save new_timeslot = #{new_timeslot.inspect}"
@arrangement.update_attributes!(params[:arrangement])
success = true
respond_to do |format|
if success
format.html { redirect_to @arrangement, notice: 'Arrangement was successfully updated.' }
else
format.html { render action: "edit" }
end
end
end
这是控制台输出:
# These are before the old_timeslot and new_timeslot variables are saved
"old_timeslot = #<Timeslot id: 17306, location_id: 3, arrangement_id: nil, timeslot: \"2014-01-10 17:00:00\", created_at: \"2013-05-20 04:03:30\", updated_at: \"2014-01-11 01:35:55\">"
"new_timeslot = #<Timeslot id: 17306, location_id: 3, arrangement_id: 839, timeslot: \"2014-01-10 17:00:00\", created_at: \"2013-05-20 04:03:30\", updated_at: \"2014-01-11 01:35:55\">"
# These are after the old_timeslot and new_timeslot variables are saved
"after save old_timeslot = #<Timeslot id: 17306, location_id: 3, arrangement_id: nil, timeslot: \"2014-01-10 17:00:00\", created_at: \"2013-05-20 04:03:30\", updated_at: \"2014-01-11 01:37:09\">"
"after save new_timeslot = #<Timeslot id: 17306, location_id: 3, arrangement_id: 839, timeslot: \"2014-01-10 17:00:00\", created_at: \"2013-05-20 04:03:30\", updated_at: \"2014-01-11 01:35:55\">"
Started PUT "/arrangements/839" for 127.0.0.1 at 2014-01-10 19:37:09 -0600
Processing by ArrangementsController#update as HTML
Parameters: {"utf8"=>"✓", "authenticity_token"=>"REBgw/kRwlclqS670aIcIZ1Ug6kgxr/itEevwMQO2w8=", "arrangement"=>{"family_name"=>"smith", "location_id"=>"3", "date"=>"01/10/2014", "timeslot_id"=>"17306", "need"=>"myNeed", "notes"=>"mynotes", "user_id"=>"66"}, "button"=>"", "id"=>"839"}
User Load (0.4ms) SELECT `users`.* FROM `users` WHERE `users`.`id` = 2 LIMIT 1
Setting Load (0.4ms) SELECT `settings`.* FROM `settings`
Arrangement Load (0.4ms) SELECT `arrangements`.* FROM `arrangements` WHERE `arrangements`.`id` = 839 LIMIT 1
Timeslot Load (0.2ms) SELECT `timeslots`.* FROM `timeslots` WHERE `timeslots`.`id` = 17306 LIMIT 1
CACHE (0.0ms) SELECT `timeslots`.* FROM `timeslots` WHERE `timeslots`.`id` = 17306 LIMIT 1
(0.1ms) BEGIN
(0.3ms) UPDATE `timeslots` SET `arrangement_id` = NULL, `updated_at` = '2014-01-11 01:37:09' WHERE `timeslots`.`id` = 17306
(53.5ms) COMMIT
(0.1ms) BEGIN
(0.2ms) COMMIT
Redirected to http://localhost:3000/arrangements/839
Completed 302 Found in 168ms (ActiveRecord: 55.5ms)
答案 0 :(得分:1)
首先,您尝试连续两次保存同一记录是很奇怪的。只要这些记录的id相同,第二次保存就应该覆盖第一次。
另一方面,由于Rails 2.0左右Rails具有“脏”对象和属性的概念。所以很可能是作业
new_timeslot.arrangement_id = @arrangement.id
如果arrangement_id
属性已经具有值@arrangement.id
,则实际上不会更改任何内容。因此,new_timeslot
对象不会被标记为“脏”,并且rails可以跳过save!
作为优化措施。即使您事先在数据库中更新了相同的记录,new_timeslot
仍然没有被标记为'脏',因为您在另一个实例中执行了此操作。
因此,要么您要保存两个不同的记录,那么您应该将至少一个的id更改为nil
(或创建一个新记录并使用相同的属性对其进行初始化)或者您只想更新使用new_timeslot
属性进行记录,然后没有理由在save!
上致电old_timeslot
。