Question

考虑以下示例数据：

Name    Email  RowRank   PartitionRank
----    -----  -------   -------------
a1      e1      1         1
a1      e1      2         1
a2      e2      1         2
a2      e2      2         2
a2      e2      3         2

我正在尝试编写一个按名称+电子邮件对数据进行分区的查询，然后给出每个分区中一行的索引和分区本身的数量（最后两列列出预期的输出）。

我一直尝试使用各种查询，使用ROW_NUMBER生成RowRank很容易，但是我无法使用4个排名函数（NTILE，RANK，DENSE_RANK或ROW_RANK）中的任何一个生成分区排名。我确信这应该是可能的，但不能自己加入。

以下是一个示例查询：

SELECT Name, Email,
        ROW_NUMBER() OVER (PARTITION BY Name, Email ORDER BY Email, DisplayName) AS RowRank,
        NTILE(1) OVER (PARTITION BY Name, Email ORDER BY Email, DisplayName) AS PartitionRank
FROM Zone.MyTable

有人可以帮我解决分区排名是否正确。

Answer 1

整个输出需要DENSE_RANK（）（无分区）

SELECT Name, Email,
        ROW_NUMBER() OVER (PARTITION BY Name, Email ORDER BY Email, DisplayName) AS RowRank,
        DENSE_RANK() OVER (ORDER BY Name, Email) AS PartitionRank
FROM Zone.MyTable

Answer 2

这对我有用：

select *
  , RowRank = row_number() over (partition by Name order by Email)
  , PartitionRank = dense_rank() over (order by Name)
from MyTable

SQL Fiddle with demo

Answer 3

select * ,row_number() over (order by Salary desc) as [Row_number],rank() over (order by Salary desc) as [Rank],dense_rank() over (order by Salary desc) as [Dense_rank],ntile(3) over (order by Salary desc) as [Ntile] from Employee

检查下面给出的URL中的示例

http://www.freshcodehub.com/Article/50/implement-ranking-functions-in-sql-server

Sql Server - 使用排名函数计算分区

3 个答案: