我有三个型号
公司(id,name)
public function relations()
{
return array(
'specializations' => array(self::MANY_MANY, 'Specialization', 'company_specialization(company_id, spec_id)'),
);
}
专业化(id,alias,name)
public function relations()
{
return array(
'companies' => array(self::MANY_MANY, 'Company', 'company_specialization(spec_id, company_id)'),
);
}
CompanySpecialization (company_id,spec_id)
我希望通过专业化别名属性找到所有具有特定专业化集的公司。
我尝试了这个,但它返回所有记录而没有限制(yii-debug sql query here)。
$criteria=new CDbCriteria;
$criteria->with=array(
'specializations' => array(
'select'=>false,
'joinType'=>'INNER JOIN',
'condition'=>'specializations.alias IN ("spec1","spec2","spec3")',
)
);
$model=Company::model()->findAll($criteria);
通常我希望以活动记录方式获得下一个sql查询:
SELECT c.name AS name
FROM company c
INNER JOIN company_specialization cs ON (c.id=cs.company_id)
INNER JOIN specialization s ON (s.id=cs.spec_id)
WHERE (s.alias IN ("spec1","spec2","spec3))
答案 0 :(得分:0)
几乎就在那里。您应该使用CDbCriteria::addInCondition()
$criteria=new CDbCriteria;
$criteria->with=array(
'specializations' => array(
'select'=>false,
'joinType'=>'INNER JOIN',
)
);
$criteria->addInCondition('specializations.alias', array("spec1","spec2","spec3"));;
$model=Company::model()->findAll($criteria);
答案 1 :(得分:0)
解决方案只是添加
$criteria->together=true;