我正在尝试加入三张桌子,但我无法理解这种方法...
我完成了加入2桌
var entryPoint = dbContext.tbl_EntryPoint
.Join(dbContext.tbl_Entry,
c => c.EID,
cm => cm.EID,
(c, cm) => new
{
UID = cm.OwnerUID,
TID = cm.TID,
EID = c.EID,
}).
Where(a => a.UID == user.UID).Take(10);
我想将 tbl_Title 表格包含在 TID PK中,并获取标题字段。
非常感谢
答案 0 :(得分:161)
我认为使用基于语法的查询会更容易:
var entryPoint = (from ep in dbContext.tbl_EntryPoint
join e in dbContext.tbl_Entry on ep.EID equals e.EID
join t in dbContext.tbl_Title on e.TID equals t.TID
where e.OwnerID == user.UID
select new {
UID = e.OwnerID,
TID = e.TID,
Title = t.Title,
EID = e.EID
}).Take(10);
您应该添加orderby
子句,以确保Top(10)
返回正确的前十项。
答案 1 :(得分:61)
这是未经测试的,但我相信语法应该适用于lambda查询。当您使用此语法连接更多表时,您必须深入查看新对象以获得要操作的值。
var fullEntries = dbContext.tbl_EntryPoint
.Join(
dbContext.tbl_Entry,
entryPoint => entryPoint.EID,
entry => entry.EID,
(entryPoint, entry) => new { entryPoint, entry }
)
.Join(
dbContext.tbl_Title,
combinedEntry => combinedEntry.entry.TID,
title => title.TID,
(combinedEntry, title) => new
{
UID = combinedEntry.entry.OwnerUID,
TID = combinedEntry.entry.TID,
EID = combinedEntry.entryPoint.EID,
Title = title.Title
}
)
.Where(fullEntry => fullEntry.UID == user.UID)
.Take(10);
答案 2 :(得分:1)
var entryPoint = (from ep in dbContext.tbl_EntryPoint
join e in dbContext.tbl_Entry on ep.EID equals e.EID
join t in dbContext.tbl_Title on e.TID equals t.TID
where e.OwnerID == user.UID
select new {
UID = e.OwnerID,
TID = e.TID,
Title = t.Title,
EID = e.EID
}).Take(10);