Question

我正试图操纵一个Eloquent对象。下面是Json中对象的结构，以便于阅读。每条记录都是一个问题的答案。您会注意到记录中有两个实例（1和2）。

以下是目标：

1）将所有相关的“答案”字段放入一个记录中（按“实例”分组 - 定义关系 - 如下所述）

2）按实例对记录进行分组。我需要所有带有“instance”的记录：“1”组合在一起，所有记录都带有“instance”：“2”组合在一起。

3）维护集合中的项目以传递给视图

期望的格式:(注意记录如何按“实例”分组，我现在可以遍历它们，这是我的目标）

[
    {
       "1": "John",
       "2": "A",
       "3": "Livingston",
       "instance": "1"
    },
    {
       "1": "Jake",
       "2": "B",
       "3": "Miller"
       "instance": "2"
    }
]

RAW OUTPUT：

[
[
    {
        "id": 1241,
        "project_id": 1080,
        "user_id": 1,
        "question_id": 46,
        "answer": "John",
        "instance": "1"
    },
    {
        "id": 1271,
        "project_id": 1080,
        "user_id": 1,
        "question_id": 46,
        "answer": "Jake",
        "instance": "2"
    }
],
[
    {
        "id": 1242,
        "project_id": 1080,
        "user_id": 1,
        "question_id": 47,
        "answer": "A",
        "instance": "1"
    },
    {
        "id": 1272,
        "project_id": 1080,
        "user_id": 1,
        "question_id": 47,
        "answer": "B",
        "instance": "2"
    }
],

[
    {
        "id": 1240,
        "project_id": 1080,
        "user_id": 1,
        "question_id": 48,
        "answer": "Livingston",
        "instance": "1"
    },
    {
        "id": 1279,
        "project_id": 1080,
        "user_id": 1,
        "question_id": 48,
        "answer": "Miller",
        "instance": "2"
    }
],

]

这里有一些代码让我接近理想的结果，但如果每个实例中的答案数量不完全匹配，则抛出偏移量错误：

        // the $answers object is the one I'm trying to manipulate. 
        // for context, $answers->toJson() gives the raw json output above
            foreach($answers as $answer)
            {
                $numOfAnswers = $answer->count();
            }


            $i = 0;
            while ($i < $numOfAnswers) {
                $resource{$i} = $answers->fetch($i);  
                $i++;
            }   

            // This returns 'John' on the first loop, 'Jake' on the second loop, etc.
            foreach($resource as $answerGroup)
            {
                 $answerGroup->fetch('answer')[1]
            }

Answer 1

将键和数字索引组合在一个数组中并不是一个好的风格......无论如何我操纵多维数组，这就是我得到的：

  $answers = [];
  foreach ($initialCollection as $item) {
        foreach ($item as $answer) {
            $instance = $answer['instance'];
            if (!isset($answers[$instance])) {
                $answers[$instance] = [
                    'instance'  => $instance,
                    'answers'   => [$answer['answer']],
                ];
            } else {
                $answers[$instance]['answers'][] = $answer['answer'];
            }
        }
    }

试试这个并检查结果。您可能希望从中创建新的集合。

Laravel / PHP操作集合记录

1 个答案: