Question

我如何在python中执行此操作：

x = [1,2,3,4,5,6]
for i in x:
    if i == 4:
       -restart the loop from beginning-
    else:
        print i

所以这里它将打印到4然后重复循环

Answer 1

这个怎么样：

x = [1,2,3,4,5,6]
restart = True
while restart:
    for i in x:
        # add any exit condition!
        # if foo == bar:
        #   restart = False
        #   break
        if i == 4:
           break
        else:
            print i

Answer 2

你不能直接。使用 itertools.cycle

for idx, val in enumerate(itertools.cycle(range(4))):
    print v
    if idx>20:
        break

idx 用于打破infiniteloop

Answer 3

也许这样的事情？但它会永远循环......

x = [ ..... ]
restart = True
while restart:
    for i in x:
        if i == 4:
            restart = True
            break
        restart = False
        print i

Answer 4

只需用while语句换行。

while True:
    restart = False
    for i in x:
        if i == 4:
            restart = True
            break
        else:
            print i
    if not restart:
        break

Answer 5

使用while循环：

x=[1,2,3,4,5,6]
i=0
while i<len(x): 
    if x[i] == 4:
        i=0
        continue
    else:
        print x[i]
    i+=1

Answer 6

我会为那个

使用递归函数

def fun(x):
    for i in x:
        if i == 4:
            fun(x)
        else:
            print i
    return;

x = [1,2,3,4,5,6]
fun(x)

如何在python中重启“for”循环？

6 个答案: