Question

提前抱歉，开发代码和网络访问位于两个单独的平台上，因此我无法复制和粘贴。

在我的jsp中，如果有一个列表定义如下：

<form:form id=""fm-form commandname="command" action="$actionURL" onsubmit="return false;">
// what does this commandName="command" do?  I see it in several places in the code
// and it all has to do with dropdown lists.
.
.
.
.
.
<form:select id="fm-explosives2" path="fm-explosives2" items="${command.explosiveList}"       onchange="populateDensity(); populatetntEquiv()";/>

然后我调用.js文件中的makeCaluculations（）...

function makeCalculations(){
...
var explosiveNames = new array();
.
.
.
var explosiveList = DWRUtil.getValue("fm-explosive2"); 
// this should have all the names from the dropdown list - or am I wrong?

// then I try to populate the array to be used later...
for (var i=0; i < explosiveList.length; i++){
      var explosive = explosiveList[i];

      alert("explosive name is: " + explosive.explosives);  // all NULL values!!! Why? Help!
      explosiveNames.push(explosive.explosives);
      more code .....

}

}

问题：这个commandName =“command”（在.jsp源代码中）是做什么的？我在代码中的几个地方看到它这一切都与下拉列表有关。任何人吗？

Answer 1

根据您的评论澄清。你的功能看起来像......

function makeCalculations(){
var explosiveNames = [];
var explosives = DWRUtil.getValue("fm-explosive2"); 
// this should have all the names from the dropdown list - or am I wrong?

// then I try to populate the array to be used later...
for (var i=0; i < explosives.length; i++){
      var explosivenames = explosiveList[i];

      alert("explosive name is: " + explosives[i].explosives);
      explosiveNames.push(explosives[i].explosives);
}

Answer 2

explosive未在您的整个代码中定义。
在循环中，它不应是explosive.explosives，它应该是explosiveList[i].explosives，其中explosives可以是explosiveList[i]

所以，基本上用explosive.explosives代替在您的代码中explosiveList[i].explosives，它应该可以正常工作。

如何从列表中获取所有值？

2 个答案: