Question

我有一个C＃文件上传，用于从DocX文档中提取XML标签，我面临的问题是，当文件上传时，错误“文件被另一个进程使用”来了起来。尝试删除文档表明IIS进程管理器正在使用它。

有没有办法阻止我的代码让它继续运行？

<script runat="server">


 //foreach (DataRow row in table.Rows)
 //{
  //  string dbColumnNames = (selectedData.ToString());
     //send files
 //}

    public string _TempFileLocation = ""; //Used to locate Word Document File Path 


        //THE USER UPLOAD CONTROL. users use this to upload the document to the server
        public void XMLextractor(string _filePath)
        {
            //XML extraction code
           displayFilepath.Text = _filePath;
           _TempFileLocation = _filePath;

        }

        //names the script manager which will be used when the user attempts to upload a form / gives an error if they incorrectly attempt to upload
        protected void UploadButton_Click(object sender, EventArgs e)
        {
            //if file is located
            if (FileUploadControl.HasFile)
            {
                try
                {
                    //allow content type of document / docx
                    if (FileUploadControl.PostedFile.ContentType == "application/vnd.openxmlformats-officedocument.wordprocessingml.document")
                    {

                        if (FileUploadControl.PostedFile.ContentLength < 10485760) // 10mb)
                        {
                            //name the filename, find the path of the name
                            string filename = Path.GetFileName(FileUploadControl.FileName);
                            //path of server upload (we just need to save it as a variable to be found on the next page, as it will be made / deleted
                            FileUploadControl.SaveAs(Server.MapPath("~/") + filename);
                            //update the label with file uploaded
                            StatusLabel.Text = "Upload status: File uploaded!";

                            XMLextractor(Server.MapPath("~/") + filename);

                            //move onto template wizard page
                            //Response.Redirect("http://portal.acoura.com/admin/templatewizard.aspx", false);

                            WordprocessingDocument _TempDoc = WordprocessingDocument.Open(Server.MapPath("~/") + filename, true);

                            XDocument xdoc = XDocument.Load(Server.MapPath("~/") + filename);
                            //query to find particular descendants
                            var lv1s = from document in xdoc.Descendants("table")
                                       select new
                                       {
                                           Header = document.Attribute("name").Value,
                                           Children = document.Descendants("tag")
                                       };

                            //Loop through results
                            StringBuilder result = new StringBuilder();
                            foreach (var lv1 in lv1s)
                                        {
                                            result.AppendLine(lv1.Header);
                                            foreach (var lv2 in lv1.Children)
                                            result.AppendLine("     " + lv2.Attribute("name").Value);
                                        }

                            //the label should contain the content controls of the document, using the class, XMLfromDocument                                                                                                                                           
                            labelContentControls.Text = fileUpload_Displayx(XMLfromDocument.GetContentControls(_TempDoc));
                        }

                        else
                            //display the size the file needs to be less than
                            StatusLabel.Text = "Upload status: The file has to be less than 10mb!";
                    }
                    else
                        //tell the user only docx files are accepted
                        StatusLabel.Text = "Upload status: Only DOCX files are accepted!";
                }
                catch (Exception ex)
                {
                    //display the exception message, in which case it would be either size / type / if it's present
                    StatusLabel.Text = "Upload status: The file could not be uploaded. The following error occured: " + ex.Message;
                }


            }

        }

        //needs to be replaced with the variable found in descendants / var tagContent
        public string fileUpload_Displayx(XElement _contentcontrol)
        {
            string str = "";
            str = _contentcontrol.Name.ToString();

            return str;
        }


   //public static displayDatabase(object sender, EventArgs e)
  // {

   //}
   //run the validate button on templatewizard, will mark up any problems or give green light


   //if red, allow users to replace fields in the left column, from ones in the atabase on the right


   //display upload button when validation is succesful. When Upload button runs, Take to new 
   // / existing page of reports, allow users to download this 






</script>

Answer 1

您正在打开该文件而不在此行关闭它：

WordprocessingDocument _TempDoc = WordprocessingDocument.Open(Server.MapPath("~/") + filename, true);

然后用xDocument.Load（）再次打开它：

XDocument xdoc = XDocument.Load(Server.MapPath("~/") + filename);

我认为这是发生错误的地方。

如果您首先处理XDocument需要处理的所有内容，然后打开并关闭WordProcessingDocument.Open()行以获取内容控件，那么您应该没问题。

基本上只有一个进程可以一次打开并读取或修改文件，因此如果需要执行来自两个不同源的两个操作，则必须在文件上按顺序执行它们。

您也可以通过FileStream打开文件，然后将内容加载到内存中并加载到XDocument，从而无需在XDocument和WordProcessingDocument之前打开文件两次同时进行。

希望这有帮助！

上传表单不起作用 - 另一个进程正在使用文件

1 个答案: