SSIS:Oracle多行到一列输出,没有STRAGG

时间:2010-01-20 20:03:30

标签: .net sql oracle ssis

当ID相同时,希望生成以逗号分隔的语言列表。

表1:

ID | LangID
1    1
1    2
1    3
2    3
2    4
3    1

表2:

ID | Language
1    English
2    Spanish
3    French
4    German

想要生成如下结果:

ID | Languages
1    English, Spanish, French
2    French, German
3    English

我尝试过的事情:

Stragg - SSIS给了我“无效的标识符”

SYS_Connect_By_Path - 无法弄清楚如何加入id以转换为字符串语言。

有什么建议吗?

2 个答案:

答案 0 :(得分:6)

有多种方法可以执行字符串聚合以生成以逗号分隔的列表 - 请参阅this link for more details。根据链接中的示例,尝试:

SELECT x.id,
       LTRIM(MAX(SYS_CONNECT_BY_PATH(x.language,','))
       KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
  FROM (SELECT a.id,
               b.language,
               ROW_NUMBER() OVER (PARTITION BY a.id ORDER BY b.language) AS curr,
               ROW_NUMBER() OVER (PARTITION BY a.id ORDER BY b.language) -1 AS prev
          FROM TABLE_1 a
          JOIN TABLE_2 b ON b.id = a.langid) x
GROUP BY x.id
CONNECT BY prev = PRIOR curr AND x.id = PRIOR x.id
START WITH curr = 1;

答案 1 :(得分:2)

对于11g,请查看listagg function

select t1.id, listagg(t2.language, ', ') within group (order by t2.language)
from t1, t2
where t1.langId = t2.id
group by t1.id;