我正在尝试转换从我的方法中检索到的十六进制值，compareHexaRGB和ASCII字符，我想知道输出将产生什么。我不知道我做错了还是错过了代码。
用于将十六进制值转换为ASCII的extractMessage（）方法的代码：
public class extractMessage
{
private static String[][] char1;
private static String[][] char2;
private static String[][] in;
private static String[][] combine;
public static void extractMessage(String[][] inn, String[][] comb)
{
in = inn;
combine = comb;
}
public static void printString2DArray(String[][] in)
{
for (int i = 0; i < in.length; i++)
{
for(int j = 0; j < in[i].length; j++)
{
System.out.println(in[i][j] + " ");
}
System.out.println();
}
}
public static void charExtract()
{
compareHexaRGB hexRGB = new compareHexaRGB();
char1 = hexRGB.getCheck_hex2();
char2 = hexRGB.getCheck_hex4();
combine = new String[char1.length][char1[0].length];
for(int i = 0; i < char1.length; i++)
{
for(int j = 0; j < char1[i].length; j++)
{
//concatenate string
combine[i][j] = char1[i][j] + char2[i][j];
}
}
System.out.println("Char 1 + Char 2: ");
printString2DArray(combine);
}
public static String convertHexToString()
{
extractMessage em = new extractMessage();
StringBuilder sb = new StringBuilder();
StringBuilder temp = new StringBuilder();
String out = em.charExtract(); //error stated incompatible types: void cannot be converted to String
int decimal;
for(int i = 0; i < out.length(); i += 2)
{
String output = out.substring(i, (i + 2));
decimal = Integer.parseInt(output, 16);
sb.append((char)decimal);
temp.append(decimal);
}
System.out.println("Output: " + temp.toString());
return sb.toString();
}
}
其次，我仍然无法从检索到的值中消除NULL值。有人说我需要添加一个位置来保存字符，在这种情况下是NULL值。我已经这样做了，但是当我尝试运行代码时，我们又回到这里，发生了nullpointerexception。我还是java新手，缺乏处理java数组和高级java的经验，但我很想学习。 Java是非常有趣的语言，我希望有一天我能掌握这门语言。
compareHexaRGB（）的代码：
public class compareHexaRGB
{
private static int w;
private static int h;
private static BufferedImage img;
private static BufferedImage img2;
private static String[][] check_hex2;
private static String[][] check_hex4;
private static String[][] not_stega2;
private static String[][] not_stega4;
public static void compareHexaRGB(BufferedImage image, BufferedImage image2, int width, int height) throws IOException
{
w = width;
h = height;
img = image;
img2 = image2;
}
public void check() throws IOException
{
getPixelRGB1 pixel = new getPixelRGB1();
getPixelData1 newPD = new getPixelData1();
int[] rgb;
int count = 0;
int[][] pixelData = new int[w * h][3];
check_hex2 = new String[w][h];
check_hex4 = new String[w][h];
for(int i = 0; i < w; i++)
{
for(int j = 0; j < h; j++)
{
rgb = newPD.getPixelData(img, i, j);
for(int k = 0; k < rgb.length; k++)
{
pixelData[count][k] = rgb[k];
}
if(pixel.display_imgHex2()[i][j].equals(pixel.display_img2Hex2()[i][j]))
{
System.out.println("\nPixel values at position 2 are the same." + "\n" + pixel.display_imgHex2()[i][j] + " " + pixel.display_img2Hex2()[i][j]);
not_stega2[i][j] = pixel.display_img2Hex2()[i][j]; // i've done the same as check_hex2 and check_hex4 method but why the error still occur?
}
if(pixel.display_imgHex4()[i][j].equals(pixel.display_img2Hex4()[i][j]))
{
System.out.println("\nPixel values at position 4 are the same." + "\n" + pixel.display_imgHex4()[i][j] + " " + pixel.display_img2Hex4()[i][j]);
not_stega4[i][j] = pixel.display_img2Hex4()[i][j];
}
if(!pixel.display_imgHex2()[i][j].equals(pixel.display_img2Hex2()[i][j]))
{
System.out.println("\nPixel values at position 2 are not the same." + "\n" + pixel.display_imgHex2()[i][j] + " " + pixel.display_img2Hex2()[i][j]);
check_hex2[i][j] = pixel.display_img2Hex2()[i][j];
System.out.println("\nOutput Hex 2: " + check_hex2[i][j]);
}
if(!pixel.display_imgHex4()[i][j].equals(pixel.display_img2Hex4()[i][j]))
{
System.out.println("\nPixel values at position 4 are not the same." + "\n" + pixel.display_imgHex4()[i][j] + " " + pixel.display_img2Hex4()[i][j]);
check_hex4[i][j] = pixel.display_img2Hex4()[i][j];
System.out.println("\nOutput Hex 4: " + check_hex4[i][j]);
}
if(!pixel.display_imgHex2()[i][j].equals(pixel.display_img2Hex2()[i][j]) || (!pixel.display_imgHex4()[i][j].equals(pixel.display_img2Hex4()[i][j])))
{
System.out.println("\nOne of the pixel values at position 2 and 4 are not the same." + "\n" + pixel.display_imgHex2()[i][j] + " " + pixel.display_img2Hex2()[i][j] + "\n" + pixel.display_imgHex4()[i][j] + " " + pixel.display_img2Hex4()[i][j]);
if(!pixel.display_imgHex2()[i][j].equals(pixel.display_img2Hex2()[i][j]) || (pixel.display_imgHex2()[i][j].equals(pixel.display_img2Hex2()[i][j])))
{
check_hex2[i][j] = pixel.display_img2Hex2()[i][j];
System.out.println("\nOutput Hex 2: " + check_hex2[i][j]);
}
if(!pixel.display_imgHex4()[i][j].equals(pixel.display_img2Hex4()[i][j]) || (pixel.display_imgHex4()[i][j].equals(pixel.display_img2Hex4()[i][j])))
{
check_hex4[i][j] = pixel.display_img2Hex4()[i][j];
System.out.println("\nOutput Hex 4: " + check_hex4[i][j]);
}
}
count++;
System.out.println("\nOutput Count: " + count);
}
}
}
public String[][] getCheck_hex2()
{
return check_hex2;
}
public String[][] getCheck_hex4()
{
return check_hex4;
}
public String[][] getCheck_notStega2()
{
return not_stega2;
}
public String[][] getCheck_notStega4()
{
return not_stega4;
}
}
希望快速消除这些问题。感谢任何帮助！
答案 0 :(得分：0)
public static void charExtract()
{ ...
}
和
String out = em.charExtract(); //error stated incompatible types
charExtract()上调用静态方法em？
你在那些String[][]数组中存储了什么？
char1 = hexRGB.getCheck_hex2();
char2 = hexRGB.getCheck_hex4();
我们无法帮助您将内容转换为任何内容。
目前我认为你真的不想处理“十六进制”数字;在int上执行计算要比在数字的任何字符串表示上更容易执行。
答案 1 :(得分：0)
正如我所看到的，您的代码中有两个缺陷::
1。如果charExtract（）方法是静态的，那么您需要以静态方式访问它，如::
String out = extractMessage.charExtract();
2. 其次，当您将charExtract（）中的值存储到String变量“out”时 所以你需要从charExtract（）方法返回一个字符串，将其声明为
public static String charExtract()
{ ...
}
并从charExtract返回一些值，如：
return combine[o][1];