Question

我无法弄清楚查询...

我试图从凭证表中获取总价值。

月份始终以unix时间格式不断变化（上个月或下个月）。

PHP

$date = date('Y-m-d', $unixtime);
$month = date('m', $unixtime);
$year = date('Y', $unixtime);

数据库'user_voucher_history'：

history_id | user_id |  value | used |  datetime(unixtime)

the smallest date record was 2013-05-05!

当前查询

SELECT 
      IFNULL(SUM(value), 0) AS total 
   FROM user_voucher_history
   WHERE user_id = 2 AND used = 1 AND MONTH(FROM_UNIXTIME(datetime)) < {$month}

上面的代码：当谈到2014年和01月时，它返回0，所以尝试了下面的不同代码，仍然是0。

查询

SELECT 
  IFNULL(SUM(value), 0) AS total 
FROM 
  user_voucher_history,
  ( SELECT MIN(DATE(FROM_UNIXTIME(datetime))) FROM user_voucher_history) AS min_date
WHERE 
  user_id = 2 AND used = 1
  AND (DATE(FROM_UNIXTIME(datetime)) BETWEEN min_date AND {$date} )
  AND (MONTH(FROM_UNIXTIME(datetime)) < {$month} )
  AND (YEAR(FROM_UNIXTIME(datetime)) < {$year} )

请建议!!!

Answer 1

据我了解，您希望显示与所选YEAR和MONTH匹配的正确行

试一试

SELECT 
   IFNULL(SUM(value), 0) AS total 
   FROM user_voucher_history
   WHERE user_id = 2 AND used = 1 AND 
   MONTH(FROM_UNIXTIME(datetime)) < {$month} AND 
   YEAR(FROM_UNIXTIME(datetime)) = {$year}

Answer 2

我想你想聚合几个月：

SELECT SUM(value)
  FROM user_voucher_history
  WHERE FROM_UNIXTIME(datetime) BETWEEN :mindate AND :maxdate
  GROUP BY MONTH(FROM_UNIXTIME(datetime))

顺便说一下，您确实希望将datetime的类型更改为DATETIME之类的日期类型。

MySQL查询选择MIN Date＆amp;月

2 个答案: