Spring Jdbc查询执行

时间:2010-01-20 19:16:55

标签: sql sql-server spring jdbc spring-jdbc

有谁知道我可以用什么Spring Jdbc模板方法来执行这个'upsert',或者另外一种方法也可以在一次数据库调用中执行操作?

UPDATE jasper_report SET Uri = 'update' WHERE ReportId = 99;
IF @@ROWCOUNT = 0 AND Exists(Select 1 FROM report Where Id = 99)
BEGIN   
    INSERT INTO jasper_report  (ReportId, Uri) VALUES (99, 'insert') 
END;

2 个答案:

答案 0 :(得分:3)

原来我很接近,但忘记了一步。

我不得不将查询本身更改为:

BEGIN 
  UPDATE jasper_report SET Uri = ? WHERE ReportId = ? 
  IF @@ROWCOUNT = 0 AND EXISTS(SELECT 1 FROM report WHERE Id = ?) 
  BEGIN 
       INSERT INTO jasper_report  (ReportId, Uri) VALUES (?, ?) 
  END 
END

然后在我的Dao中只需要使用Spring's JdbcTemplate update method。它看起来像这样:

@Repository("jasperReportsDao")
public class JasperReportsDaoImpl extends JdbcTemplate implements JasperReportsDao {

    @Override
    public void saveJasperReport(JasperReport report) {
        // If a record already exists, do an update, otherwise, do an insert
        int rowsAffected = this.update(UPSERT_JASPER_REPORT, new Object[] { report.getUri(), report.getId(),
                               report.getId(), report.getId(), report.getUri()} );

        if(log.isDebugEnabled()) { log.debug("Rows affected: " + rowsAffected); }
    }
}

答案 1 :(得分:1)

不应该是Not Exists

无论如何,我认为没有Not Exists它会正常工作,因为@@ROWCOUNT已经提供了这些信息:

UPDATE jasper_report SET Uri = 'update' WHERE ReportId = 99;
IF @@ROWCOUNT = 0 
BEGIN   
    INSERT INTO jasper_report (ReportId, Uri) VALUES (99, 'insert') 
END;