Question

我有一个用户显示活动的源流，我必须在通过ajax调用加载页面后通知用户新活动。以下是代码

views.py

@login_required
def new_activity(request):

    context = {}
    response = {}
    latest_activity = []        
    prev_activity_id = request.GET.get('activity_id')
    #get the latest activity from news feed
    time_stamp = Activity.objects.get(pk = prev_activity_id).created
    latest_activity = Activity.objects.filter(created__gt = time_stamp)
    activity_count  = latest_activity.count()


    #Handle multiple activities
    if activity_count == 1:
        updated_id = latest_activity.id
    elif activity_count > 1:
        updated_id = latest_activity[0].id
    else:
        updated_id = prev_activity_id

    context['activities'] = latest_activity

    template = render_to_string('activities/new_activity_template.html', context,    context_instance=RequestContext(request))
    response['template'] = template
    response['updated_id'] = updated_id
    response['activity_count'] = activity_count
    response['success'] = 'success'

    return HttpResponse(simplejson.dumps(response), mimetype='application/json')

AJAX

(function new_activity() {

    setTimeout(function() {
            var activity_id = null

        $.ajax({
            url: "/activities/all/new_activity/?activity_id="+activity_id,
            type: "GET",
            success: function(response) {
            $('#id_new_activity').empty();
            $('#id_new_activity').append(response.template);
                console.log(response.success);

                    //if activity_id is null get the activity id for first time
                    //if activity_id is not null update the activity_id from the response

                activity_id = response.updated_id;



            },
            dataType: "json",
            complete: new_activity,
            timeout: 2000
        })
    }, 5000);
})();

如果在我的活动模型中创建了任何新对象，我需要在每次调用new_activity后更新最新的acitivity_id。此外，我还需要在加载页面时第一次传递activity_id。

我不知道如何在我的ajax调用中这样做。

Answer 1

在用户浏览器中保存不是activity_id，而是保存latest_activity日期。当ajax查询并且有新活动时，在用户浏览器中保存最新活动的新日期，并且对于下一个ajax查询发送该日期，因此服务器端应用程序将仅在该日期之后发送活动。

通过django中的ajax实现通知

1 个答案: