Question

我的问题是当我点击提交form_validation-＆gt; run（）返回false

这是我的控制器

public function change_pass()
{
$this->load->helper('form');
$this->load->library('form_validation');
$this->form_validation->set_rules('new_pass', 'New Password', 'required|matches[cnew_pass]');
$this->form_validation->set_rules('cnew_pass','Confirm Password','required|matches[new_pass]');

if($this->form_validation->run()==FALSE)
{
die(print_r("Always go here"));
}
}

以下是我的观点.................

    <?php echo form_open('tickets/change_pass'); ?>
     <center>
<table>

            <tr>
                <td<label for="new_pass">New Password:</label>
                    <input type="password" name="new_pass" class="form-control"><?php echo form_error('new_pass');?>
                </td>
            </tr>

            <tr>
                <td<label for="cnew_pass">Confirm New Password:</label>
                    <input type="password" name="cnew_pass" class="form-control"><?php echo form_error('cnew_pass');?>
                </td>
            </tr>
        </table>

        <input type="submit" name="change" class="btn btn-success"> <input type="reset" class="btn btn-danger">
    </center>

Answer 1

嗨，你必须首先在单独的函数中加载视图。这将是你的代码。

public function index()
    {

        $this->load->helper('form');

        $this->load->view('your view name');

    }

Answer 2

我认为您需要检查是否单击了提交按钮，然后单击验证

这是您需要在控制器中更改的代码

public function change_pass() {
        $this->load->helper('form');
        $this->load->library('form_validation');

        if ($this->input->post('submit')) {

        $this->form_validation->set_rules('new_pass', 'New Password', 'required|matches[cnew_pass]');
        $this->form_validation->set_rules('cnew_pass', 'Confirm Password', 'required|matches[new_pass]');

        if ($this->form_validation->run() == FALSE) {
            die(print_r("Always go here"));
        }
        }
        $this->load->view('change_pass');
    }

因为在验证时不检查总是错误的我认为它应该对你有帮助

form_validation-＆gt; run（）返回false Codeigniter

2 个答案: