Question

新手AJAX在这里，我想再次查询或select *from在我的数据库上点击按钮并更改textarea内容？如何使用AJAX执行此操作。

这是我的代码。

<textarea id="CKUPDATEALL">
<?php
$result = mysqli_query($con,"SELECT *FROM home WHERE ANNOUNCE_TYPE='WELCOMENOTE' ORDER BY ANNOUNCE_NUMBER DESC limit 0,1");
while($row = mysqli_fetch_array($result))
{
echo $row['ANNOUNCEMENTS'];
}
?>
</textarea>

Answer 1

不，你可以设置你的php文件来检查Ajax调用中传递的不同变量。在Ajax响应中成功查找php文件中定义的不同变量。因此，您可以调用Ajax.php来获取10个不同的Ajax调用和响应。只需要正确设置它。

$(document).ready(function(){
$("#my_button").on('cick',function(){
 Var name = $('#thisinputid').val();
 $.ajax({
     url: "getval.php",
     type: "POST",
     data : { fullname : name },
     success: function(data) {
           $("#CKUPDATEALL").val(data);
     }
});
});

然后在php文件中检查$ _post ['fullname']。

Answer 2

尝试 $.ajax() ，

$(function(){
    $.ajax({
      url:'get_announcement.php',
      type:'POST',
      data:{type:'announcement'},
      success:funtion(d){
         $('#CKUPDATEALL').val(d);
      }
    });
});

<强> get_announcement.php

<?php
    // type is announcement
    if(isset($_POST['type']) and $_POST['type']=='announcement'){
       $result=mysqli_query($con,"SELECT * FROM home WHERE 
                 ANNOUNCE_TYPE='WELCOMENOTE' ORDER BY ANNOUNCE_NUMBER DESC limit 1");
       while($row = mysqli_fetch_array($result)){
          echo $row['ANNOUNCEMENTS'];
       }
       echo 'not found';
    }
?>

Answer 3

说这是你的按钮

<input type="button" id="my_button" value="Cick"/>

的Ajax

$(document).ready(function(){
  $("#my_button").on('cick',function(){
     $.ajax({
         url: "getval.php",
         type: "POST",
         data : {'type':'textarea'},
         success: function(data) {
               $("#CKUPDATEALL").val(data);
         }
  });
});

在getval.php中

<?php
  if(isset($_POST['type']) && trim($_POST['type']) == 'textarea'){
    $result = mysqli_query($con,"SELECT * FROM home WHERE ANNOUNCE_TYPE='WELCOMENOTE' ORDER BY ANNOUNCE_NUMBER DESC limit 0,1");
    while($row = mysqli_fetch_array($result)){
       echo $row['ANNOUNCEMENTS'];
    }
    die();
  }
?>

使用AJAX更改文本区域内容

3 个答案: