Question

我有以下代码。基本上我想从上到下搜索这个多维数组的键，但忽略具有$ignoreKey指定的键的子数组。正如您在"array_key_exists"逻辑中看到的那样，它目前是为一维数组而构建的。我尝试了一些示例但遇到了问题（所以我的1D代码如下所示）。

如果一切按计划进行，我会"thirtyfromgroup1"回应。

为了实现这一目标，我需要在以下内容中进行哪些更改？

$keyCheck = "30";
$ignoreKey = "group2";

if (array_key_exists($keyCheck, $topLevel)) {
      echo $topLevel[$keyCheck];
}

 $topLevel = array( 
           "group1" => array
                               (
                               "12" => "twelve", 
                               "30" => "thirtyfromgroup1" 
                               ),
            "group2" => array
                               (
                               "14" => "fourteen", 
                               "30" => "thirty" 
                                ),
             "group3" => array
                               (
                               "12" => "twelve", 
                               "26" => "thirty" 
                                ),
                   );

Answer 1

假设您只想忽略数组顶层的键，并且只是在第二级搜索键：

$keyCheck = "30";
$ignoreKey = "group2";

$topLevel = array( 
    "group1" => array(
        "12" => "twelve", 
        "30" => "thirtyfromgroup1"
    ),
    "group2" => array(
        "14" => "fourteen", 
        "30" => "thirty" 
    ),
    "group3" => array(
        "12" => "twelve", 
        "26" => "thirty" 
    ),
);

foreach($topLevel as $topKey => $topValue)
{
    if ($topKey == $ignoreKey)
        continue;

    foreach($topValue as $subKey => $subValue)
    {
        if ($subKey == $keyCheck)
            echo $subValue;
    }

    /* Alternatively:

    if (isset($topValue[$keyCheck]))
        echo $topValue[$keyCheck];

    */
}

递归多维数组搜索但排除某个子数组？

1 个答案: