Question

我的数据库表中有以下条目

eventName(varchar 100) -> myEvent
date(timestamp) -> 2013-03-26 09:00:00

我试图使用以下查询;

SELECT * 
FROM eventList 
WHERE `date` BETWEEN UNIX_TIMESTAMP(1364256001) AND UNIX_TIMESTAMP(1364342399)

即2013-03-26 00:00:01和2013-03-26 23:59:59

但它给了我0个结果。

我试图在没有运气的情况下扩大日期范围，但肯定会有范围内的结果。

感谢任何帮助。

Answer 1

尝试：

SELECT * 
FROM eventList 
WHERE  `date` BETWEEN FROM_UNIXTIME(1364256001) AND FROM_UNIXTIME(1364342399)

或者

SELECT * 
FROM eventList WHERE  `date` 
BETWEEN '2013-03-26 00:00:01' AND '2013-03-26 23:59:59'

Answer 2

试试这个。它对我有用。

SELECT * 
FROM eventList 
WHERE DATE(date) 
BETWEEN '2013-03-26' AND '2013-03-27'

Answer 3

您只需将日期转换为UNIX_TIMESTAMP即可。您可以这样编写查询：

SELECT *
FROM eventList
WHERE
  date BETWEEN
      UNIX_TIMESTAMP('2013/03/26')
      AND
      UNIX_TIMESTAMP('2013/03/27 23:59:59');

如果您没有指定时间，MySQL会假定00:00:00为给定日期的时间。

Answer 4

SELECT * FROM `orders` WHERE `order_date_time`  BETWEEN 1534809600 AND 1536718364

Answer 5

尝试以下方法：

SELECT * FROM eventList WHERE
date BETWEEN 
STR_TO_DATE('2013/03/26', '%Y/%m/%d')
AND
STR_TO_DATE('2013/03/27', '%y/%m/%d')

Answer 6

@Amaynut谢谢

SELECT * 
FROM eventList 
WHERE date BETWEEN UNIX_TIMESTAMP('2017-08-01') AND UNIX_TIMESTAMP('2017/08/01');

如上所述，代码有效，我的问题解决了。

Answer 7

尝试以下代码。就我而言。希望这会有所帮助！

    select id,total_Hour,
    (coalesce(weekday_1,0)+coalesce(weekday_2,0)+coalesce(weekday_3,0)) as weekday_Listing_Hrs,
    (coalesce(weekend_1,0)+coalesce(weekend_2,0)+coalesce(weekend_3,0)) as weekend_Listing_Hrs
    from
    select *,
    listing_duration_Hour-(coalesce(weekday_1,0)+coalesce(weekday_2,0)+coalesce(weekday_3,0)+coalesce(weekend_1,0)+coalesce(weekend_2,0)) as weekend_3 
    from 
    (
    select * , 
    case when date(Start_Date) = date(End_Date) and weekday(Start_Date) in (0,1,2,3,4) 
         then timestampdiff(hour,Start_Date,End_Date)
         when date(Start_Date) != date(End_Date) and weekday(Start_Date) in (0,1,2,3,4) 
         then 24-timestampdiff(hour,date(Start_Date),Start_Date)
         end as weekday_1,  
    case when date(Start_Date) != date(End_Date) and weekday(End_Date) in (0,1,2,3,4) 
         then timestampdiff(hour,date(End_Date),End_Date)
         end as weekday_2,
    case when date(Start_Date) != date(End_Date) then    
    (5*(DATEDIFF(date(End_Date),adddate(date(Start_Date),+1)) DIV 7) + 
    MID('0123455501234445012333450122234501101234000123450',7 * WEEKDAY(adddate(date(Start_Date),+1))
    + WEEKDAY(date(End_Date)) + 1, 1))* 24 end as  weekday_3,
    case when date(Start_Date) = date(End_Date) and weekday(Start_Date) in (5,6) 
         then timestampdiff(hour,Start_Date,End_Date)
         when date(Start_Date) != date(End_Date) and weekday(Start_Date) in (5,6) 
         then 24-timestampdiff(hour,date(Start_Date),Start_Date)
         end as weekend_1,  
    case when date(Start_Date) != date(End_Date) and weekday(End_Date) in (5,6) 
         then timestampdiff(hour,date(End_Date),End_Date)
         end as weekend_2
    from 
    TABLE_1
    )

Answer 8

尝试一下对我有用

SELECT * from bookedroom
    WHERE UNIX_TIMESTAMP('2020-8-07 5:31')
        between UNIX_TIMESTAMP('2020-8-07 5:30') and
        UNIX_TIMESTAMP('2020-8-09 5:30')

两个时间戳之间的MYSQL查询

8 个答案: