我的代码存在以下问题,但编译正确:
值类型const char不能用于初始化char *
类型的实体
有人能帮助我吗?我可以运行奇怪的代码,但我无法使用它创建一个makefile。这对我来说很奇怪。
int SpliString(struct dict_word *entry, const char *str)
{
long word_length,j,k;
int yearIndex;
char *buffer;
char *endOfYears;
char *endOfYear;
char *endOfDefinition;
char *endOfWord = strstr(str, "_#_");
//Sets the first num bytes of the block of memory pointed by ptr
//to the specified value (related as an unsigned char)
memset(entry, 0, sizeof(struct dict_word));
// If '_#_' is not found, it's NULL
if (endOfWord)
{
// Calculating word legth; 'str' points to start of word, 'endofWord' points to '_#_' that is just after word
word_length = endOfWord - str;
// Copying data into the word
strncpy(entry->words, str, word_length);
// 'endOfYears' points to '_#_,' but wee need to find follow '_#_'
// therefore there is added 3 in order to skip curremnt '_#_
endOfYears = strstr(endOfWord+3, "_#_");
if (endOfYears)
{
word_length = endOfYears - (endOfWord+3);
// Skips _#_
buffer = endOfWord+3;
yearIndex = 0;
j = 0;
// Finds next year in the line, it stops if all 10 years is filled
// or end of years string is reached
while(yearIndex<10 && buffer+j<endOfYears)
{
// Stores year in the buffer, with converting 'stirng' to 'int'
entry->year[yearIndex] = atoi(buffer+j);
// check year for negative...
if (entry->year[yearIndex]<=0)
return 0;
// Locating substring; 'j' is current offset from beginning of buffer
endOfYear = strchr(buffer+j, '_');
if (endOfYear)
{
j = endOfYear - buffer;
j++;
yearIndex++;
}
else
{
break;
}
}
//endOfYears points to '_#_' that separatates 'years' and 'definition'
//and there is needed to find '_#_' between 'definition' and 'synonyms'
//therefore it skips '_#_' that separatates 'years' and 'definition',
//+3, because '_#_' has length = 3
endOfDefinition = strstr(endOfYears+3, "_#_");
if (endOfDefinition)
{
word_length = endOfDefinition - (endOfYears+3);
k = 0;
for(j=0; j<word_length; j++)
{
// Skips '_#_'
if (endOfYears[j+3]==',')
{
entry->eng_synonyms[k] = ' ';
k++;
}
else if (endOfYears[j+3]>='a' && endOfYears[j+3]<='z')
{
entry->eng_synonyms[k] = endOfYears[j+3];
k++;
}
else if (endOfYears[j+3]!='_')
{
return 0;
}
}
k = 0;
word_length = (str+strlen(str)) - (endOfDefinition+3);
for(j=0; j<word_length; j++)
{
if (endOfDefinition[j+3]==',')
{
entry->heb_synonyms[k] = ' ';
k++;
}
else if (endOfDefinition[j+3]>='A' && endOfDefinition[j+3]<='Z')
{
entry->heb_synonyms[k] = endOfDefinition[j+3];
k++;
}
else if (endOfDefinition[j+3]!='_')
{
return 0;
}
}
}
// Check for legality
// Check all symbols of 'entry->words'
// calculate length and supress warning
for(j=0;j<(int)strlen(entry->words);j++)
{
if (entry->words[j]<'a' || entry->words[j]>'z')
return 0;
}
return 1;
}
}
return 0;
}
答案 0 :(得分:3)
使用
const char *buffer;
const char *endOfWord = strstr(str, "_#_");
自信的OP正在用C ++编译。
// C
char *strstr(const char *s1, const char *s2);
// C++
const char* strstr(const char* s1, const char* s2);
char* strstr( char* s1, const char* s2);
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