我正在尝试从json文件中提取嵌套值。我想打印出每个“id”键的每个值。我认为我很接近,但无法弄清楚为什么obj类型从dict变为列表,然后为什么我无法解析该列表。 这是我正在使用的json的链接:http://hastebin.com/ratevimixa.tex
这是我目前的代码:
#!/usr/bin/env python
#-*- coding: utf-8 -*-
import json
json_data = open('JubJubProductions.json', 'r+')
jdata = json.loads(json_data.read().decode("utf-8"))
def recursion(dict):
for key, value in dict.items():
if type(value) == type(dict):
if key != "paging":
for key, value in value.items():
if isinstance (value,list):
print key
# place where I need to enter list comprehension?
if type(value) == type(dict):
if key == "id":
print " id found " + value
if key != "id":
print key + " 1st level"
if key == "id":
print key
else:
if key == "id":
print "id found " + value
if __name__ == '__main__':
recursion(jdata)
现在我正在使用它,它将返回一个id值,但不是全部:
#!/usr/bin/env python
#-*- coding: utf-8 -*-
import json
json_data = open('jubjubProductions', 'r+')
jdata = json.loads(json_data.read().decode("utf-8"))
def id_generator(d):
for k, v in d.items():
if k == "id":
yield v
elif isinstance(v, dict):
for id_val in id_generator(v):
yield id_val
if __name__ == '__main__':
for _ in id_generator(jdata):
print (_)
答案 0 :(得分:18)
JSON可能包含需要搜索的对象列表:
Python 2.7版本:
def item_generator(json_input, lookup_key):
if isinstance(json_input, dict):
for k, v in json_input.iteritems():
if k == lookup_key:
yield v
else:
for child_val in item_generator(v, lookup_key):
yield child_val
elif isinstance(json_input, list):
for item in json_input:
for item_val in item_generator(item, lookup_key):
yield item_val
Python 3.x版本:
def item_generator(json_input, lookup_key):
if isinstance(json_input, dict):
for k, v in json_input.items():
if k == lookup_key:
yield v
else:
yield from item_generator(v, lookup_key)
elif isinstance(json_input, list):
for item in json_input:
yield from item_generator(item, lookup_key)
答案 1 :(得分:11)
def id_generator(dict_var):
for k, v in dict_var.items():
if k == "id":
yield v
elif isinstance(v, dict):
for id_val in id_generator(v):
yield id_val
这将创建一个迭代器,它将在键“id”下的任何级别上产生每个值。示例用法(打印所有这些值):
for _ in id_generator(some_json_dict):
print(_)
答案 2 :(得分:0)
一点更简洁的代码(在python 3.x中)。
def parse_json_recursively(json_object, target_key):
if type(json_object) is dict and json_object:
for key in json_object:
if key == target_key:
print("{}: {}".format(target_key, json_object[key]))
parse_json_recursively(json_object[key], target_key)
elif type(json_object) is list and json_object:
for item in json_object:
parse_json_recursively(item, target_key)
json_object = {"key1": "val1", "key2": [{"key3":"val3", "key4": "val4"}, 123, "abc"]}
target_key = "key3"
parse_json_recursively(json_object, target_key) # Ouput key3: val3
答案 3 :(得分:0)
def get_val(j, s, v=None):
for k in j:
if v == None and k == s:
return j[k]
elif v != None and k == s and v == j[k]:
return True
elif v != None and k == s and v != j[k]:
return False
elif isinstance(j[k], dict):
return get_val(j[k], s, v)
您可以将with与下面的json列表一起使用
for l in j:
r = get_val(l, 'key')
print(r)
for l in j:
r = get_val(l, 'mac', '00-60-2F-5A-04-51')
print(r)