Question

任何人都可以帮助我处理if和else语句吗？每当我输入内容时，它只会说“退出再见”，这应该只在我输入-0时发生。我的老师一周都不见了，所以我没有人请求帮助。

package game;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Random;

import javax.swing.JOptionPane;

public class GameFrame {

/**
 * @param args
 */
public static void main(String[] args) {
     // num1 - Variable to store the first value
       // num2 - Variable to store the second value
       // answer - Variable to accept user input
        int num1, num2, answer=0;

        /*@reader - The reader which accepts user input*/
        BufferedReader reader = new BufferedReader (new     InputStreamReader(System.in));
        /*@quit - Variable used to exit the program*/
        boolean quit = false;
        /*@generator - The Random number generator*/
        Random generator = new Random();

        while (quit == false)
        {
          //Generate First Random Number between 1-100
          num1 = generator.nextInt(100);
          //Generate First Random Number between 1-100
          num2 = generator.nextInt(100);
          //Displays the math equation
        String input = JOptionPane.showInputDialog(null,num1+ "+" + num2 + " = ");
          //Accepts the user's input and converts it to int value
          int number = Integer.parseInt(input);
          //Lets assume if user enters -99, it means they want to exit the program
          if (answer == -0)
          {
          JOptionPane.showMessageDialog(null, "Exit Program: Good Bye!\n");
              quit = true;
          }else if (answer == (num1+num2))
              JOptionPane.showMessageDialog(null,"Correct Answer!\n");
          else{
              JOptionPane.showMessageDialog(null,"Incorrect Answer\n");
    }
}
 }
}

Answer 1

如果您以前从未制作过GUI程序，那么尝试将控制台程序转移到GUI程序并不是一件容易的事。您需要了解事件驱动的编程。我建议您查看Swing tutorials

但有些提示。你想要一个“半gui”程序。您只需使用JOptionPane s作为输入。假设你想得到一个数字输入。你会做这样的事情

String numberString = JOptionPane.showInputDialog(null, "Enter a Number");
int number = Integer.parseInteger(numberString);

执行第一行后，会自动弹出输入窗格。要求输入。结果是一个String，所以你有来解析它以得到一个数字。

此外，如果您只想 diplay 一条消息，请使用

JOptionPane.showMessageDialog(null, message);

你可以这样做，显示一些结果。在上述情况下，当您只想显示消息时，您不需要使其等于任何内容。因此，您可以使用System.out.println()代替JOPtionpane.showMesageDialog()而不是reader.readLine()，而不是JOptionPane.showInputDialog()，而是使用{{1}}

尝试一下，如果你被卡住了就回来。

另请参阅documentation for JOptionPane以查看其他可能的弹出对话框。

Answer 2

尝试这是在我的电脑上运行

  /**
  *
 * @author sandeepk
 */
  import java.io.BufferedReader;
  import java.io.InputStreamReader;
  import java.util.Random;

  import javax.swing.JOptionPane;

  public class GameFrame {

/**
 * @param args
 */
public static void main(String[] args) {
 // num1 - Variable to store the first value
    // num2 - Variable to store the second value
    // answer - Variable to accept user input
    int num1, num2, answer = 0;

    /*@reader - The reader which accepts user input*/
    BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
    /*@quit - Variable used to exit the program*/
    boolean quit = false;
    /*@generator - The Random number generator*/
    Random generator = new Random();

    while (quit == false) {
        //Generate First Random Number between 1-100
        num1 = generator.nextInt(100);
        //Generate First Random Number between 1-100
        num2 = generator.nextInt(100);
        //Displays the math equation
        String input = JOptionPane.showInputDialog(null, num1 + "+" + num2 + " = ");
        //Accepts the user's input and converts it to int value
        int number = Integer.parseInt(input);
        //Lets assume if user enters -99, it means they want to exit the program
        System.out.println("number  " + number);
        if (number == 0) {
            JOptionPane.showMessageDialog(null, "Exit Program: Good Bye!\n");
            quit = true;
        } else if (number == (num1 + num2)) {
            JOptionPane.showMessageDialog(null, "Correct Answer!\n");
        } else {
            JOptionPane.showMessageDialog(null, "Incorrect Answer\n");
        }
    }
}
 }



 if my code is run and you satisfy then please vote me thanks.

如何在窗口上打开此程序？

2 个答案: