Question

我使用此SQL查询从不同的表中获取结果

<?
$sql = "SELECT gtem.gname AS itmnme, gvendor.gname AS vendor, gtem.col AS qty
FROM gpopackageline
LEFT JOIN gpo ON gpo.gpoid = gpopackageline.gpoid
LEFT JOIN gtem ON gpopackageline.gtemid = gtem.gtemid
LEFT JOIN gvendor ON gitem.gvendorid = gvendor.gvendorid
WHERE gpopackageline.gpoid='".$sdo['swelid']."' ";
$row = dblib_get_row_list($sql);
?>
<td class="contents51" width="100%"><?=$row['itmnme']?> </td>
<td class="contents51" width="100%"><?=$row['vendor']?> </td>
<td class="contents51" width="100%"><?=$row['qty']?> </td>

问题是我只得到1并打印出第一个结果。当我在phpmyadmin中测试查询时，我得到了所有结果任何人都可以帮忙解决这个问题谢谢

Answer 1

您需要通过while或foreach循环搜索结果，具体取决于您的逻辑。

例如

<?
$sql = "SELECT gtem.gname AS itmnme, gvendor.gname AS vendor, gtem.col AS qty
FROM gpopackageline
LEFT JOIN gpo ON gpo.gpoid = gpopackageline.gpoid
LEFT JOIN gtem ON gpopackageline.gtemid = gtem.gtemid
LEFT JOIN gvendor ON gitem.gvendorid = gvendor.gvendorid
WHERE gpopackageline.gpoid='".$sdo['swelid']."' ";
$getRows = dblib_get_row_list($sql);  //Assuming this returns everything in an assoc array
foreach($getRows as $row) {
?>
<td class="contents51" width="100%"><?=$row['itmnme']?> </td>
<td class="contents51" width="100%"><?=$row['vendor']?> </td>
<td class="contents51" width="100%"><?=$row['qty']?> </td>
<?php
}
?>

Answer 2

我不知道你的dblib_get_row_list是什么回归。如果它返回数组，那么它应该按预期工作。

 <?
    $sql = "SELECT gtem.gname AS itmnme, gvendor.gname AS vendor, gtem.col AS qty
    FROM gpopackageline
    LEFT JOIN gpo ON gpo.gpoid = gpopackageline.gpoid
    LEFT JOIN gtem ON gpopackageline.gtemid = gtem.gtemid
    LEFT JOIN gvendor ON gitem.gvendorid = gvendor.gvendorid
    WHERE gpopackageline.gpoid='".$sdo['swelid']."' ";
    $result = dblib_get_row_list($sql);
    foreach($result as $row ){
    echo "<td class='contents51' width='100%'>".$row['itmnme']."</td>";
    echo "<td class='contents51' width='100%'>".$row['vendor']."</td>";
    echo "<td class='contents51' width='100%'>".$row['qty']."</td>";

    }

使用php显示mysql的所有结果的问题

2 个答案: