Question

我试图执行我的程序并收到此错误消息在这里我的主要

int numofsect=2;
unsigned char** hash_table;
hash_table = new unsigned char*[numofsect];
for (int i=0; i < numofsect; i++)
    hash_table[i] = new unsigned char[CryptoPP::SHA::DIGESTSIZE];
char** tab;
tab = new char*[numofsect];
for (int i=0; i< numofsect; i++)
    tab[i] = new char[5];
int* tabsize;
tabsize = new int[2];
tabsize[0]=5;
tabsize[1]=5;

printf("Type sections:\n");
printf("Sect1: ");
scanf("%s", tab[0]);
printf("\nSect2: ");
scanf("%s", tab[1]);
hasher(numofsect, tab, tabsize, hash_table);
printf("Your hashed tab is:\n");
printf("hash sect1: ");
printf("%s",hash_table[0]);
printf("\nhash sect2: ");
printf("%s",hash_table[1]);

delete[] hash_table;
delete[] tab;
delete[] tabsize;

这是我的哈希函数：

void hasher (int num_of_sect, char** sect_tab, int* size_of_sect_tab, unsigned char** hash_tab )
{
  for (int i=0 ; i<=num_of_sect ; i++) { // i is the number of each secion
    byte haSha1[CryptoPP::SHA::DIGESTSIZE]; //Byte table to calculate the hash of the section i
    byte* chaine = (byte*)malloc(sizeof(byte)*size_of_sect_tab[i]); //chaine reiceive the byte stream of the section i
    for (int j=0 ; j<size_of_sect_tab[i]; j++) //j is the n-th byte of the section
        chaine[j]=sect_tab[i][j]; //copy each byte of the sect_tab in the chaine


    CryptoPP::SHA().CalculateDigest(haSha1, chaine, size_of_sect_tab[i]); //Hash the section and return it in haSha1
    for (int j=0; j<CryptoPP::SHA::DIGESTSIZE; j++) //j is the n-th byte of the hashed section
        hash_tab[i][j]=haSha1[j]; //copy each byte of the hash to the hash_table
  }
}

感谢您的帮助

Answer 1

在以下代码中i = num_of_sect时，您正在访问sect_tab数组的边界之外：

 chaine[j]=sect_tab[i][j];

你不能拥有

for (int i=0 ; i<=num_of_sect ; i++) {

因为您传递tab = new char * [numofsect];

请记住，数组的索引编号为0到size.1。

Answer 2

hasher函数中的for循环不应该是<=，而应该是<，如下所示：

  for (int i=0 ; i < num_of_sect ; i++)

这可能就是问题所在。请使用调试器并逐步完成它，您很快就会发现问题所在。调试器是我们最好的朋友！

基于零的索引！

0xC0000005：访问冲突读取位置0x00000000 hashfunc

2 个答案: