Question

我正在尝试转换一个对象，即将具有多个字段的用户转换为XML。问题是我在尝试序列化ILIST成员时遇到异常。以下是我正在使用的代码：

var stringwriter = new System.IO.StringWriter(); 
var serializer = new XmlSerializer(User.GetType()); <!-- Getting exception here -->
serializer.Serialize(stringwriter, User); 
return stringwriter.ToString();

我的用户看起来像这样：

class User
{       public virtual string Name{ get; set; }
        public virtual DateTime? LastUpdated { get; set; }

        public virtual int? ContactId { get; set; }

        public virtual IList<Sector> Sectors { get; set; }
        public virtual AccessLevel AccessLevel { get; set; }
        public virtual IList<UserRole> UserRole { get; set; }
}

有没有办法可以检查我正在序列化的对象的类成员是否可序列化，然后调整该特定成员的逻辑。我对用户类的控制较少。 :(所以任何我可以扩展我的代码来处理IList成员的方式将是首选。

Answer 1

旧式XML序列化无法处理接口 - 它需要具体的类型。

但是，您可以使用较新的DataContractSerializer。

以下是基于您的代码的示例：

using System;
using System.Collections.Generic;
using System.IO;
using System.Runtime.Serialization;
using System.Text;
using System.Xml;

namespace Demo
{
    [DataContract(Namespace = "")]
    public class User
    {
        [DataMember]
        public virtual string Name
        {
            get;
            set;
        }

        [DataMember]
        public virtual DateTime? LastUpdated
        {
            get;
            set;
        }

        [DataMember]
        public virtual int? ContactId
        {
            get;
            set;
        }

        [DataMember]
        public virtual IList<string> Sectors
        {
            get;
            set;
        }
    }

    internal class Program
    {
        private void run()
        {
            User user = new User();

            user.Sectors = new[] {"One", "Two", "Three"};
            user.Name = "Test Name";

            // Serialize

            var result = new StringBuilder();
            DataContractSerializer serializer = new DataContractSerializer(user.GetType());

            using (var stringWriter = new StringWriter(result))
            using (var xmlWriter    = XmlWriter.Create(stringWriter, new XmlWriterSettings { Indent = true } ))
            {
                serializer.WriteObject(xmlWriter, user);
            }

            string serialisedToString = result.ToString();

            Console.WriteLine(serialisedToString);

            // Deserialize

            using (var stringReader = new StringReader(serialisedToString))
            using (var xmlReader    = XmlReader.Create(stringReader))
            {
                user = (User) serializer.ReadObject(xmlReader);
            }

            Console.WriteLine(user.Name);
        }

        private static void Main()
        {
            new Program().run();
        }
    }
}

如何将包含ILIST成员的对象序列化为XML？

1 个答案: