Question

我有一个表示为父/子关系树的文件夹结构。现在让我们想象下面的树：

- Folder1

---子文件夹1-1

---- Subfolder1-1-1

--- Subfolder2

---- Subfolder2-1

- Folder2

现在我显然要使用导航属性，因此当在Subfolder1-1内时，我得到了代表ParentFolder的属性Folder1。

我现在如何走上树以从文件夹名称中生成连接的字符串？

例如，当从Subfolder1-1-1调用此方法时，我希望字符串为Folder1.Subfolder1-1.Subfolder1-1-1，并且在从Subfolder2-1进行调用时，我希望字符串为Folder1.Subfolder2.Subfolder2-1。< / p>

我考虑过递归，但以下不起作用：

public string GetCompleteFolderName(string delimiter)
{
    string folderName = null;

    if (FolderParent != null)
    {
        folderName += GetCompleteFolderName(FolderParent) + delimiter;
    }

    return folderName;
}

private string GetCompleteFolderName(Folder folder)
{
    string folderName = null;
    if (folder != null)
    {
        folderName = folder.Name;
    }

    return folderName;
}

Answer 1

认为这应该做的伎俩

public class Folder
{
    public Folder ParentFolder { get; set; }
    public string Name { get; set; }

    public Folder()
    {
    }
    public string GetFullFolderName(string delimiter = ".")
    {
        var folderName = string.Empty;
        if (ParentFolder != null)
        {
            folderName += ParentFolder.GetFullFolderName(delimiter) + delimiter + Name;
        }
        else
        {
            folderName += Name;
        }
        return folderName;
    }
}

internal class Program
{
    private static void Main(string[] args)
    {
        var f1 = new Folder {Name = "f1"};
        var f2 = new Folder {Name = "f2", ParentFolder = f1};
        var f3 = new Folder {Name = "f3", ParentFolder = f2};

        Console.WriteLine(f3.GetFullFolderName());
    }
}

输出：f1.f2.f3

向上走父母/子女关系树

1 个答案: