从phonegap中的目标C重定向到html页面

Question

我必须在收到推送通知后将我的phonegap应用程序重定向到特定的html页面。我不知道如何从pbjective c代码中做到这一点。

我想做那样的事情：

• （void）application：（UIApplication *）application didReceiveRemoteNotification：（NSDictionary *）userInfo {    //从这里redirct到html页面。 }

Answer 1

您应该创建新的视图控制器，UIWebView的子类（您可以在故事板中执行），然后在-(void)application:(UIApplication *)application didReceiveRemoteNotification:(NSDictionary *)userInfo中获取该视图控制器将您的URL作为参数传递它应该没问题，让我们说你在navigationController里面有你的网页视图，你可以这样做：

UINavigationController *navigationController = (UINavigationController*)_window.rootViewController;
    YourWebViewController *webViewController = 
                        (YourWebViewController*)[navigationController.viewControllers  objectAtIndex:0];
// pass url as a parameter (you have to create property first in your YourWebViewController class)
webViewController.urlToOpen = [NSURL URLWithString:@"http://www.google.com"];

请记住，添加到didFinishLaunchingWithOptions是很好的：

- (BOOL)application:(UIApplication *)application
didFinishLaunchingWithOptions:(NSDictionary *)launchOptions
{
    // ...

    if (launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey]) {
        [self application:application didReceiveRemoteNotification:launchOptions[UIApplicationLaunchOptionsRemoteNotificationKey]];
    }
}