Question

这是我的字符串：

        String csvFile = "Screenname,Firstname,Email,Timezone,Organization,Password,Lastname,Middlename,Gender,Birthdate\n"
            + "Test01,Test01,test01@.khalibre.com,GMT+8,Khalibre,12345,test,test,M,3/8/1980\n"
            + "Sok Dara,Dara,test02@khalibre.com,GMT-7,Khalibre,12345,Sok,Dara,,1980-d1-25\n"
            + "Test03,,test03@khalibre.com.kh,GMT+1,Khalibre,12345,test,test,M,2/2/1980\n"
            + ",Test04,test04@khalibre.com,GTM-8:00,Khalibre,12345,test,test,F,\n";

这个主要方法：

boolean firstLine = true;
    String[] readLineCSVs = csvFile.split("\n");
    for (String readLineCSV : readLineCSVs) {
        rows++;
        if (firstLine) {
            firstLine = false;
        } else {
            SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
            Readdata rd = new Readdata();
            String[] csvData = readLineCSV.split(csvSplitBy);
            int count =0;
            while(csvData[count++]!=null){
                System.out.println(count);
            }
            System.out.println(csvData[0]);
            System.out.println(csvData[1]);
            System.out.println(csvData[2]);
            System.out.println(csvData[3]);
            System.out.println(csvData[4]);
            System.out.println(csvData[5]);
            System.out.println(csvData[6]);
            System.out.println(csvData[7]);
            System.out.println(csvData[8]);
            System.out.println(csvData[9]);
        }

错误显示如下：

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 10
    at demo002.D2_F_003.readData(D2_F_003.java:38)
    at demo002.D2_F_003.main(D2_F_003.java:247)

如何抛出此异常？

Answer 1

boolean firstLine = true;
String[] readLineCSVs = csvFile.split("\n");
for (String readLineCSV : readLineCSVs) {
    rows++;
    if (firstLine) {
        firstLine = false;
    } else {
        SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd");
        Readdata rd = new Readdata();
        String[] csvData = readLineCSV.split(csvSplitBy);
        int count =0;

        try{
        while(csvData[count++]!=null){
            System.out.println(count);
        }
        System.out.println(csvData[0]);
        System.out.println(csvData[1]);
        System.out.println(csvData[2]);
        System.out.println(csvData[3]);
        System.out.println(csvData[4]);
        System.out.println(csvData[5]);
        System.out.println(csvData[6]);
        System.out.println(csvData[7]);
        System.out.println(csvData[8]);
        System.out.println(csvData[9]);
      }
      catch (ArrayIndexOutOfBoundsException e){
                    e.printStackTrace();
            }
    }

Answer 2

try{
   //Your Code
}catch(ArrayIndexOutOfBoundsException ex){
   //If error show 
}
catch(Exception e){
}

Answer 3

如果您要求如何解决错误，这看起来非常可疑：

int count =0;
while(csvData[count++]!=null){
    System.out.println(count);
}

我不确定null检查应该是什么。 String的split方法不会返回带有null元素的数组。

从异常消息（ArrayIndexOutOfBounds 10）判断，您的数组只有10个元素，但您尝试访问索引10（记住数组索引从0到长度 - 1）。您需要限制计数，以使其不会超过最后一个索引。

这至少会阻止异常：

int count = 0;
while(count < csvData.length && csvData[count++] != null) {
    System.out.println(count);
}

如何抛出ArrayIndexOutOfBoundsException的错误？

3 个答案: