Question

我有一个数组：

Array
(
[0] => Array
(
[id] => 31299
[name] => 37322426212
[ips] => 
[tech_prefix] => 
[password] => 
[id_voip_hosts] => 
[proxy_mode] => 
[auth_type] => ani
[ani] => 37322426212
[accname] => 
[protocol] => 
[port] => 
[orig_enabled] => 1
[term_enabled] => 
[orig_capacity] => 
[term_capacity] => 
[orig_rate_table] => 7
[term_rate_table] => 
[id_dr_plans] => 
[orig_groups] => 
[term_groups] => 
[notes] => 
)
[1] => Array
(
[id] => 4373
[name] => 37322983029
[ips] => 
[tech_prefix] => 
[password] => 
[id_voip_hosts] => 
[proxy_mode] => 
[auth_type] => ani
[ani] => 37322983029
[accname] => 
[protocol] => 
[port] => 
[orig_enabled] => 1
[term_enabled] => 
[orig_capacity] => 
[term_capacity] => 
[orig_rate_table] => 7
[term_rate_table] => 
[id_dr_plans] => 
[orig_groups] => 
[term_groups] => 
[notes] => 
)
[2] => Array
(
[auth_type] => ani
[name] => 37322983029
[ani] => 37322983029
[orig_enabled] => Array
(
[0] => on
)
[orig_rate_table] => 7
)
)

0,1,2的项目可能更多（3,4 ...... 10 ......等等）。我要做的是找到包含键ani和name = 37322983029的数组并替换 name使用'###'和ani清空：

[mane]=>"###",//where name = '37322983029'
[ani]=> //where ani = '37322983029'

我尝试str_replace但没有成功。怎么办呢？

Answer 1

不确定您使用str_replace的方式，但以下内容应该有效（假设ani和mane（或name？）实际上是数组中的字符串索引 - 从你的例子中不明显）：

foreach($myArray as &$val) {
  if($val['ani'] == 37322983029) {
    $val['ani'] = '';
    $val['name'] = "###";
  }
}

重要请注意使用&通过引用传递值，这样您就可以使用数组的实际元素，而不是复制...这样，当您修改{时{1}}您实际上正在修改原始数组。没有＆符号，循环中初始数组将保持不变。

另请注意 - 您的示例中不清楚您是仅要测试$val还是ani==37322983029。我相信您可以修改上面的代码以同时具备这两个条件（或参见Alexxus的答案）

完整的代码示例（已测试，正在运行）：

name=37322983029

生成输出

<?php
$a = Array(Array('a'=>4, 'b'=>5),Array('a'=>6, 'b'=>7));
echo '<pre>';
print_r($a);
foreach($a as &$v){
    if($v['a']==6) {
      $v['a'] = 12;
      $v['b'] = '';
    }
}
print_r($a);
echo '</pre>';
?>

Answer 2

我想，这就是你要找的东西：

foreach($yourArray as &$a)
{
  if($a["ani"] == 37322983029 and $a["ani"] == $a["name"])
  {
    $a["name"] = "###";
    $a["ani"] = "";
  }
}

PHP通过数组中的键替换值

2 个答案: